in-an-experiment-a-parallel-plate-capacitor-with-an-initial-capacitance-of-ci-an

Question

In an experiment, a parallel-plate capacitor with an initial capacitance of C_{i} and plate separation x is used. A layer of polystyrene with dielectric constant κ_{p} and thickness x/3 is inserted between the plates without altering the plate separation. Determine the resulting change in capacitance due to the polystyrene dielectric. Note that the capacitor is isolated and under vacuum conditions.

Accepted Answer

3C_{i}κ_{p}/(1+2κ_{p})

Answer

C_{i}/(1+2κ_{p})

Answer

3C_{i}/(1+2κ_{p})

Answer

C_{i}κ_{p}/(1+2κ_{p})