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8. Centripetal Forces & Gravitation - Part 1 of 3!
8. Centripetal Forces & Gravitation / Uniform Circular Motion / Problem 3
Problem 3

Consider a Ferris wheel rotating in the vertical plane, with the position of a cabin modeled as a point moving in a circular path. The position in the xy-plane is given by r=(15.0 m)cos[(0.500 rad/s)t]i^+(15.0 m)sin[(0.500 rad/s)t]j^\(\vec{r}\)=(15.0\(\mathrm{\ m}\))\(\cos\) [(0.500\ \(\mathrm{rad}\)/\(\mathrm{s}\))t]\(\hat{i}\)+(15.0\(\mathrm{\ m}\))\(\sin\) [(0.5\(\mathrm{00\ rad}\)/\(\mathrm{s}\))t]\(\hat{j}\) , where r is in meters, and t is in seconds. Calculate the velocity and acceleration of the cabin as functions of time.