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Physics Exam Practice Problems – Step-by-Step Guidance

Study Guide - Smart Notes

Tailored notes based on your materials, expanded with key definitions, examples, and context.

Q1. What is the total pressure at the bottom of a cylindrical container full of alcohol (density 810 kg/m³), with a diameter of 10 m and a depth of 5 m?

Background

Topic: Fluid Statics (Hydrostatic Pressure)

This question tests your understanding of how to calculate the pressure at the bottom of a fluid column, considering both atmospheric and hydrostatic pressure.

Key Terms and Formulas

  • Hydrostatic Pressure:

  • = atmospheric pressure (usually 1.01 × 105 Pa unless otherwise specified)

  • = density of the fluid (kg/m³)

  • = acceleration due to gravity (9.8 m/s²)

  • = depth of the fluid (m)

Step-by-Step Guidance

  1. Identify the known values: kg/m³, m, m/s², Pa.

  2. Calculate the hydrostatic pressure due to the alcohol: .

  3. Add the atmospheric pressure to the hydrostatic pressure: .

Try solving on your own before revealing the answer!

Final Answer: Pa

Pa$

Pa$

The total pressure is the sum of atmospheric and hydrostatic pressure.

Q2. Suppose you add 10 liters of fluid (density 1,000 kg/m³) to a large open cylindrical tank of radius 1 m. What is the rise in depth of the fluid?

Background

Topic: Volume and Geometry in Fluid Statics

This question tests your ability to relate the volume of fluid added to the change in height in a cylindrical container.

Key Terms and Formulas

  • Volume of a cylinder:

  • = volume added (m³)

  • = radius of the tank (m)

  • = change in height (m)

Step-by-Step Guidance

  1. Convert the volume from liters to cubic meters: $10= 0.01$ m³.

  2. Set up the formula for the change in height: .

  3. Rearrange to solve for : .

Try solving on your own before revealing the answer!

Final Answer: m

m$

The rise in depth is calculated by dividing the volume by the area of the base.

Q3. A rectangular block of copper (density 8,900 kg/m³) with dimensions 0.1 m × 0.1 m × 0.3 m is floating in water (density 1,000 kg/m³). What is the fraction of the block submerged?

Background

Topic: Buoyancy and Archimedes' Principle

This question tests your understanding of how to calculate the fraction of a floating object's volume that is submerged based on densities.

Key Terms and Formulas

  • Buoyant force equals weight of displaced fluid:

  • Weight of block:

  • Fraction submerged:

Step-by-Step Guidance

  1. Calculate the density ratio: .

  2. Set up the formula for fraction submerged: .

  3. Plug in the values for copper and water densities.

Try solving on your own before revealing the answer!

Final Answer: 8.9

The block will sink because its density is much greater than water.

Buoyancy diagram

Q4. A spherical piece of plastic of radius 10 cm and density 750 kg/m³ is completely submerged in water and held by a string. What is the tension in the string?

Background

Topic: Buoyancy, Forces in Fluids

This question tests your ability to calculate the tension in a string holding a submerged object, considering buoyant force and weight.

Key Terms and Formulas

  • Buoyant force:

  • Weight of object:

  • Tension:

  • Volume of sphere:

Step-by-Step Guidance

  1. Calculate the volume of the sphere: with m.

  2. Calculate the weight of the plastic: .

  3. Calculate the buoyant force: .

  4. Set up the tension formula: .

Try solving on your own before revealing the answer!

Final Answer: 25 N

After calculating the forces, the tension is found to be 25 N.

Sphere held by string underwater

Q5. Water flows through a pipe that has a radius of 5 cm and the water has a speed of 2 m/s. What is the volume flow rate of the water in the pipe?

Background

Topic: Fluid Dynamics (Continuity Equation)

This question tests your ability to calculate the volume flow rate using the area and velocity of the fluid.

Key Terms and Formulas

  • Volume flow rate:

  • Area of circle:

  • = velocity (m/s)

Step-by-Step Guidance

  1. Calculate the area of the pipe: with m.

  2. Multiply the area by the velocity to get the volume flow rate: .

Try solving on your own before revealing the answer!

Final Answer: 0.016 m³/s

m²$

m³/s$

The flow rate is the product of area and velocity.

Q6. The sound from a jack hammer has a sound intensity level of 90 dB at a distance of 30 m. What is the sound intensity?

Background

Topic: Sound Intensity and Decibels

This question tests your ability to convert sound intensity level (dB) to actual intensity (W/m²).

Key Terms and Formulas

  • Sound intensity level:

  • = reference intensity ( W/m²)

  • = sound intensity level (dB)

  • = sound intensity (W/m²)

Step-by-Step Guidance

  1. Set up the formula: .

  2. Plug in the values for and .

  3. Solve for by rearranging the formula.

Try solving on your own before revealing the answer!

Final Answer: W/m²

W/m²$

The intensity is calculated using the decibel formula.

Sound intensity diagram

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