BackSimple Harmonic Motion & Oscillations: Step-by-Step Physics Guidance
Study Guide - Smart Notes
Tailored notes based on your materials, expanded with key definitions, examples, and context.
Q1. The position of a 100 g mass oscillating on a massless spring is given by . Identify the following:
Background
Topic: Simple Harmonic Motion (SHM)
This question explores the properties of a mass-spring system undergoing simple harmonic motion, including amplitude, period, frequency, angular frequency, energy, and the relationship between kinetic and potential energy.
Key Terms and Formulas
Amplitude (): Maximum displacement from equilibrium.
Period (): Time for one complete oscillation.
Frequency (): Number of oscillations per second, .
Angular frequency (): .
Total energy (): .
Spring constant (): .
Kinetic energy () at position : .
Potential energy () at position : .
Speed at position : .
Step-by-Step Guidance
Identify the amplitude (): The amplitude is the coefficient in front of the cosine function in the position equation. Check the equation and note the value of .
Find the period (): The period is related to the argument of the cosine. The general form is , but here it's . Match this to the given equation to identify .
Calculate the frequency (): Use to find the frequency in Hz.
Determine the angular frequency (): Use or .
Find when for the first time: Set in the position equation and solve for (the first positive value).
Calculate the total energy (): Use . You'll need to find first (see below).
Find the spring constant (): Use , where is the mass in kg and is the angular frequency.
Calculate the speed at : Use , making sure all units are consistent (convert cm to m if needed).
Does the speed at depend on direction? Consider whether the formula for speed depends on the sign of velocity or just its magnitude.
Find the kinetic energy at : .
Find the potential energy at : .
Sum the kinetic and potential energies at : Add the values from the previous two steps.
Compare the total energy and the sum of kinetic and potential energies: Reflect on the principle of conservation of energy in SHM.
Try solving on your own before revealing the answer!
Final Answers:
a) Amplitude: 3.9 cm
b) Period: 0.38 s
c) Frequency: 2.63 Hz
d) Angular frequency: 16.5 rad/s
e) First at : 0.095 s
f) Total energy: 20.8 mJ
g) Spring constant: 27.3 N/m
h) Speed at cm: 41.2 cm/s
i) Direction dependence: No
j) Kinetic energy at cm: 8.49 mJ
k) Potential energy at cm: 12.3 mJ
l) Sum of energies at cm: 20.8 mJ
m) Why same? is constant in SHM.
Each answer follows from applying the relevant SHM formulas and principles as outlined above.
Q2. A 3.8-kg mass on a massless spring is set into oscillatory motion from with an initial velocity in the positive x-direction. The motion is described by a sine curve: . Answer the following:
Background
Topic: Simple Harmonic Motion (SHM) with Sine Initial Condition
This question examines SHM when the initial position is zero and the initial velocity is nonzero, leading to a sine function description. It covers amplitude, period, frequency, force, speed, and the relationship between force and velocity.
Key Terms and Formulas
Amplitude (): Maximum displacement from equilibrium.
Period (): Time for one complete oscillation.
Frequency (): .
Angular frequency (): .
Force on mass: (maximum when is maximum).
Speed: (maximum when ).
At maximum force, speed is zero (turning points); at minimum force (), speed is maximum.
Step-by-Step Guidance
Find the amplitude (): Read the maximum value of from the graph or equation.
Determine the period (): Measure the time for one complete cycle from the graph or use the equation.
Calculate the frequency (): Use .
Find when the force is maximum between 2 and 4 s: Force is maximum when is maximum (peaks of the sine curve). Identify these times from the graph.
Find the speed when force is maximum: At maximum , the mass changes direction, so speed is zero.
Find when force is minimum between 1.5 and 2.5 s: Force is minimum (zero) when (crosses equilibrium).
At minimum force, is speed minimum or maximum? At , speed is maximum in SHM.
Write the equation with values: Use amplitude and period to find and .
Find when m for the first time: Set m and solve for using the sine equation.
Find when m for the second time: Use the periodicity of the sine function to find the next value. Compare with the graph for confirmation.
Try solving on your own before revealing the answer!
Final Answers:
a) Amplitude: 0.50 m
b) Period: 4.00 s
c) Frequency: 0.25 Hz
d) Force maximum at s
e) Speed at force maximum: 0 m/s
f) Force minimum at s
g) Speed at force minimum: maximum
h)
i) First at m: 0.494 s
j) Second at m: 1.51 s (matches graph)
These answers follow from the properties of the sine function and SHM relationships.
Q3. A 0.95-kg mass attached to a vertical spring of force constant 130 N/m oscillates with a maximum speed of 0.45 m/s. Find:
a) The period of oscillation
b) The amplitude of the motion
c) The maximum magnitude of the acceleration
Background
Topic: Energy and Kinematics in SHM
This question tests your ability to relate mass, spring constant, amplitude, speed, and acceleration in a mass-spring system.
Key Terms and Formulas
Period:
Maximum speed:
Angular frequency:
Amplitude:
Maximum acceleration:
Step-by-Step Guidance
Calculate the angular frequency ():
Find the period ():
Determine the amplitude (): Use and solve for .
Calculate the maximum acceleration ():
Try solving on your own before revealing the answer!
Final Answers:
a) Period: 0.537 s
b) Amplitude: 3.85 cm
c) Maximum acceleration: 5.26 m/s2
Each value is found by applying the SHM formulas above with the given mass, spring constant, and maximum speed.
Q4. A student lowers a rock on a rope into a deep vertical hole and sets it into simple harmonic motion. The rock takes 233 seconds to complete 10 oscillations. How deep is the hole?
Background
Topic: Simple Pendulum Period and Length
This question uses the period of a simple pendulum to determine the length (depth) of the hole, assuming the rope acts as a simple pendulum.
Key Terms and Formulas
Period of a simple pendulum:
Total time for oscillations:
Acceleration due to gravity:
Step-by-Step Guidance
Find the period () for one oscillation: , where is total time and is number of oscillations.
Set up the pendulum period formula:
Rearrange to solve for :
Plug in the values for and to find (the depth of the hole).
Try solving on your own before revealing the answer!
Final Answer: 135 m
By calculating the period for one oscillation and using the simple pendulum formula, you find the depth of the hole to be approximately 135 m.