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Simple Harmonic Motion & Oscillations: Step-by-Step Physics Guidance

Study Guide - Smart Notes

Tailored notes based on your materials, expanded with key definitions, examples, and context.

Q1. The position of a 100 g mass oscillating on a massless spring is given by . Identify the following:

Background

Topic: Simple Harmonic Motion (SHM)

This question explores the properties of a mass-spring system undergoing simple harmonic motion, including amplitude, period, frequency, angular frequency, energy, and the relationship between kinetic and potential energy.

Key Terms and Formulas

  • Amplitude (): Maximum displacement from equilibrium.

  • Period (): Time for one complete oscillation.

  • Frequency (): Number of oscillations per second, .

  • Angular frequency (): .

  • Total energy (): .

  • Spring constant (): .

  • Kinetic energy () at position : .

  • Potential energy () at position : .

  • Speed at position : .

Step-by-Step Guidance

  1. Identify the amplitude (): The amplitude is the coefficient in front of the cosine function in the position equation. Check the equation and note the value of .

  2. Find the period (): The period is related to the argument of the cosine. The general form is , but here it's . Match this to the given equation to identify .

  3. Calculate the frequency (): Use to find the frequency in Hz.

  4. Determine the angular frequency (): Use or .

  5. Find when for the first time: Set in the position equation and solve for (the first positive value).

  6. Calculate the total energy (): Use . You'll need to find first (see below).

  7. Find the spring constant (): Use , where is the mass in kg and is the angular frequency.

  8. Calculate the speed at : Use , making sure all units are consistent (convert cm to m if needed).

  9. Does the speed at depend on direction? Consider whether the formula for speed depends on the sign of velocity or just its magnitude.

  10. Find the kinetic energy at : .

  11. Find the potential energy at : .

  12. Sum the kinetic and potential energies at : Add the values from the previous two steps.

  13. Compare the total energy and the sum of kinetic and potential energies: Reflect on the principle of conservation of energy in SHM.

Try solving on your own before revealing the answer!

Final Answers:

  • a) Amplitude: 3.9 cm

  • b) Period: 0.38 s

  • c) Frequency: 2.63 Hz

  • d) Angular frequency: 16.5 rad/s

  • e) First at : 0.095 s

  • f) Total energy: 20.8 mJ

  • g) Spring constant: 27.3 N/m

  • h) Speed at cm: 41.2 cm/s

  • i) Direction dependence: No

  • j) Kinetic energy at cm: 8.49 mJ

  • k) Potential energy at cm: 12.3 mJ

  • l) Sum of energies at cm: 20.8 mJ

  • m) Why same? is constant in SHM.

Each answer follows from applying the relevant SHM formulas and principles as outlined above.

Q2. A 3.8-kg mass on a massless spring is set into oscillatory motion from with an initial velocity in the positive x-direction. The motion is described by a sine curve: . Answer the following:

Background

Topic: Simple Harmonic Motion (SHM) with Sine Initial Condition

This question examines SHM when the initial position is zero and the initial velocity is nonzero, leading to a sine function description. It covers amplitude, period, frequency, force, speed, and the relationship between force and velocity.

Key Terms and Formulas

  • Amplitude (): Maximum displacement from equilibrium.

  • Period (): Time for one complete oscillation.

  • Frequency (): .

  • Angular frequency (): .

  • Force on mass: (maximum when is maximum).

  • Speed: (maximum when ).

  • At maximum force, speed is zero (turning points); at minimum force (), speed is maximum.

Step-by-Step Guidance

  1. Find the amplitude (): Read the maximum value of from the graph or equation.

  2. Determine the period (): Measure the time for one complete cycle from the graph or use the equation.

  3. Calculate the frequency (): Use .

  4. Find when the force is maximum between 2 and 4 s: Force is maximum when is maximum (peaks of the sine curve). Identify these times from the graph.

  5. Find the speed when force is maximum: At maximum , the mass changes direction, so speed is zero.

  6. Find when force is minimum between 1.5 and 2.5 s: Force is minimum (zero) when (crosses equilibrium).

  7. At minimum force, is speed minimum or maximum? At , speed is maximum in SHM.

  8. Write the equation with values: Use amplitude and period to find and .

  9. Find when m for the first time: Set m and solve for using the sine equation.

  10. Find when m for the second time: Use the periodicity of the sine function to find the next value. Compare with the graph for confirmation.

Try solving on your own before revealing the answer!

Final Answers:

  • a) Amplitude: 0.50 m

  • b) Period: 4.00 s

  • c) Frequency: 0.25 Hz

  • d) Force maximum at s

  • e) Speed at force maximum: 0 m/s

  • f) Force minimum at s

  • g) Speed at force minimum: maximum

  • h)

  • i) First at m: 0.494 s

  • j) Second at m: 1.51 s (matches graph)

These answers follow from the properties of the sine function and SHM relationships.

Q3. A 0.95-kg mass attached to a vertical spring of force constant 130 N/m oscillates with a maximum speed of 0.45 m/s. Find:

  • a) The period of oscillation

  • b) The amplitude of the motion

  • c) The maximum magnitude of the acceleration

Background

Topic: Energy and Kinematics in SHM

This question tests your ability to relate mass, spring constant, amplitude, speed, and acceleration in a mass-spring system.

Key Terms and Formulas

  • Period:

  • Maximum speed:

  • Angular frequency:

  • Amplitude:

  • Maximum acceleration:

Step-by-Step Guidance

  1. Calculate the angular frequency ():

  2. Find the period ():

  3. Determine the amplitude (): Use and solve for .

  4. Calculate the maximum acceleration ():

Try solving on your own before revealing the answer!

Final Answers:

  • a) Period: 0.537 s

  • b) Amplitude: 3.85 cm

  • c) Maximum acceleration: 5.26 m/s2

Each value is found by applying the SHM formulas above with the given mass, spring constant, and maximum speed.

Q4. A student lowers a rock on a rope into a deep vertical hole and sets it into simple harmonic motion. The rock takes 233 seconds to complete 10 oscillations. How deep is the hole?

Background

Topic: Simple Pendulum Period and Length

This question uses the period of a simple pendulum to determine the length (depth) of the hole, assuming the rope acts as a simple pendulum.

Key Terms and Formulas

  • Period of a simple pendulum:

  • Total time for oscillations:

  • Acceleration due to gravity:

Step-by-Step Guidance

  1. Find the period () for one oscillation: , where is total time and is number of oscillations.

  2. Set up the pendulum period formula:

  3. Rearrange to solve for :

  4. Plug in the values for and to find (the depth of the hole).

Try solving on your own before revealing the answer!

Final Answer: 135 m

By calculating the period for one oscillation and using the simple pendulum formula, you find the depth of the hole to be approximately 135 m.

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