for-a-satellite-moving-in-an-elliptical-path-given-by-x32cost-and-nbspand-and-nb

Question

For a satellite moving in an elliptical path given by ﻿x=−3+2cos⁡tx=-3+2\cos tx=−3+2cost﻿ and ﻿y=4+5sin⁡ty=4+5\sin ty=4+5sint﻿, eliminate the parameter ﻿ttt﻿ to express its path in the standard form of an ellipse.

Accepted Answer

﻿(x+3)24+(y−4)225=1\frac{$$(x+3)^2$$}{4}+\frac{$$(y-4)^2$$}{25}=14(x+3)2​+25(y−4)2​=1﻿

Answer

﻿(x+3)225+(y−4)24=1\frac{$$(x+3)^2$$}{25}+\frac{$$(y-4)^2$$}{4}=125(x+3)2​+4(y−4)2​=1﻿

Answer

﻿(x+3)24−(y−4)225=1\frac{$$(x+3)^2$$}{4}-\frac{$$(y-4)^2$$}{25}=14(x+3)2​−25(y−4)2​=1﻿

Answer

﻿(x+3)252−(y−4)24=1\frac{(x+3)}{25}^2-\frac{$$(y-4)^2$$}{4}=125(x+3)​2−4(y−4)2​=1﻿

For a satellite moving in an elliptical path given by x=−3+2costx=-3+2\(\cos\) tx=−3+2cost and y=4+5sinty=4+5\(\sin\) ty=4+5sint, eliminate the parameter ttt to express its path in the standard form of an ellipse.

For a satellite moving in an elliptical path given by $x=-3+2\(\cos\) t$ and $y=4+5\(\sin\) t$ , eliminate the parameter $t$ to express its path in the standard form of an ellipse.