Precalculus
x24−y225=1\(\frac{x^2}{4}\)-\(\frac{y^2}{25}\)=14x2−25y2=1
x225−y24=1\(\frac{x^2}{25}\)-\(\frac{y^2}{4}\)=125x2−4y2=1
x24+y225=1\(\frac{x^2}{4}\)+\(\frac{y^2}{25}\)=14x2+25y2=1
x225+y24=1\(\frac{x^2}{25}\)+\(\frac{y^2}{4}\)=125x2+4y2=1