Precalculus
x=π6+n,x=\(\frac{\pi}{6}\)+n,x=6π+n, where n is an integer
x=π6+nπ,2x=\(\frac{\pi}{6}\)+\(\frac{n\pi,}{2}\)x=6π+2nπ, where n is an integer
x=π6+nπ,x=\(\frac{\pi}{6}\)+n\(\pi\),x=6π+nπ, where n is an integer
x12+nπ,\(\frac{x}{12}\)+n\(\pi\),12x+nπ, where n is an integer