Precalculus
102i−102j10\(\sqrt\)2i-10\(\sqrt\)2j102i−102j
102i+102j10\(\sqrt\)2i+10\(\sqrt\)2j102i+102j
−102i−102j-10\(\sqrt\)2i-10\(\sqrt\)2j−102i−102j
−102i+102j-10\(\sqrt\)2i+10\(\sqrt\)2j−102i+102j