a-circle-has-its-center-located-at-the-point-5-3-and-its-radius-is-8-what-are-th

Question

A circle has its center located at the point ﻿(5,−3)(5, -3)(5,−3)﻿ and its radius is ﻿888﻿. What are the parametric equations that describe this circle?

Accepted Answer

﻿x=5+8cos⁡(t),y=−3+8sin⁡(t)x=5+8\cos(t),y=-3+8\sin(t)x=5+8cos(t),y=−3+8sin(t)﻿

Answer

﻿x=5+8sin⁡(t),y=−3+8cos⁡(t)x=5+8\sin(t),y=-3+8\cos(t)x=5+8sin(t),y=−3+8cos(t)﻿

Answer

﻿x=5−8cos⁡(t),y=−3−8sin⁡(t)x=5-8\cos(t),y=-3-8\sin(t)x=5−8cos(t),y=−3−8sin(t)﻿

Answer

﻿x=−3+8cos⁡(t),y=5+8sin⁡(t)x=-3+8\cos(t),y=5+8\sin(t)x=−3+8cos(t),y=5+8sin(t)﻿