BackPrecalculus Exam Study Guide: Algebraic Expressions, Exponents, Factoring, and Mixture Problems
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Algebraic Expressions and Evaluation
Evaluating Algebraic Expressions
Algebraic expressions can be evaluated by substituting given values for variables and performing the indicated operations.
Key Point: Substitute the value of the variable into the expression and simplify.
Example: Evaluate for .
Substitute:
Simplify:
Exponents and Their Properties
Laws of Exponents
The laws of exponents allow us to simplify expressions involving powers. When simplifying, always express answers with positive exponents.
Product of Powers:
Quotient of Powers:
Power of a Power:
Negative Exponent:
Example: Simplify using positive exponents only.
First, apply the power rule:
Combine:
Polynomial Operations
Multiplying Binomials
Multiplying binomials can be done using the distributive property or special formulas such as the FOIL method.
General Formula:
Example:
Apply the difference of squares:
Here, ,
Result:
Factoring by Grouping
Factoring by grouping is a method used to factor polynomials with four terms by grouping pairs of terms and factoring out common factors.
Steps:
Group terms in pairs.
Factor out the greatest common factor (GCF) from each pair.
If a common binomial factor appears, factor it out.
Example: Factor by grouping.
Group:
Factor:
Factor out :
Radicals and Rational Expressions
Multiplying Radical Expressions
To multiply radical expressions, use the property and simplify if possible.
Example: Multiply
Combine under one radical:
Simplifying Rational Expressions
Rational expressions can be simplified by factoring numerators and denominators and canceling common factors.
Example: Simplify
Factor numerator:
Multiply numerators and denominators:
Simplify:
Note: and are negatives of each other, so
Final answer:
Simplifying Complex Rational Expressions
Complex rational expressions involve fractions within fractions. Simplify by finding a common denominator for the inner fractions, then simplify the overall expression.
Example: Simplify
First, simplify
So,
Now, divide by :
Combine:
Factor
Final answer:
Mixture Problems
Solving Mixture Problems
Mixture problems involve combining solutions of different concentrations to achieve a desired concentration. Set up an equation based on the amount of pure substance in each solution.
Key Formula: Amount of pure substance = volume × concentration
Example: How many liters of pure water should be mixed with a 5-L solution of 80% acid to produce a mixture that is 70% water?
Let = liters of pure water to add.
5 L of 80% acid = 20% water, so water in original solution: L
After adding liters of water, total water:
Total volume:
Set up equation:
Solve for :
L
Summary Table: Key Algebraic Properties
Property | Formula | Example |
|---|---|---|
Product of Powers | ||
Quotient of Powers | ||
Power of a Power | ||
Negative Exponent | ||
Difference of Squares |