Pump DesignThe piston diameter of a certain hand pump is 0.5 inch. The quality-control manager determines that the diameters are normally distributed, with a mean of 0.5 inch and a standard deviation of 0.004 inch. The machine that controls the piston diameter is recalibrated in an attempt to lower the standard deviation. After recalibration, the quality-control manager randomly selects 25 pistons from the production line and determines that the standard deviation is 0.0025 inch. Was the recalibration effective? Use the α = 0.01 level of significance.
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 56m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 17m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - ExcelBonus23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - ExcelBonus28m
- Confidence Intervals for Population Means - ExcelBonus25m
- 8. Sampling Distributions & Confidence Intervals: Proportion2h 10m
- 9. Hypothesis Testing for One Sample5h 8m
- Steps in Hypothesis Testing1h 6m
- Performing Hypothesis Tests: Means1h 4m
- Hypothesis Testing: Means - ExcelBonus42m
- Performing Hypothesis Tests: Proportions37m
- Hypothesis Testing: Proportions - ExcelBonus27m
- Performing Hypothesis Tests: Variance12m
- Critical Values and Rejection Regions28m
- Link Between Confidence Intervals and Hypothesis Testing12m
- Type I & Type II Errors16m
- 10. Hypothesis Testing for Two Samples5h 37m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - ExcelBonus28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - ExcelBonus12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - ExcelBonus9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - ExcelBonus21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - ExcelBonus12m
- Two Variances and F Distribution29m
- Two Variances - Graphing CalculatorBonus16m
- 11. Correlation1h 24m
- 12. Regression3h 33m
- Linear Regression & Least Squares Method26m
- Residuals12m
- Coefficient of Determination12m
- Regression Line Equation and Coefficient of Determination - ExcelBonus8m
- Finding Residuals and Creating Residual Plots - ExcelBonus11m
- Inferences for Slope31m
- Enabling Data Analysis ToolpakBonus1m
- Regression Readout of the Data Analysis Toolpak - ExcelBonus21m
- Prediction Intervals13m
- Prediction Intervals - ExcelBonus19m
- Multiple Regression - ExcelBonus29m
- Quadratic Regression15m
- Quadratic Regression - ExcelBonus10m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA2h 29m
9. Hypothesis Testing for One Sample
Performing Hypothesis Tests: Variance
Problem 8.4.3
Textbook Question
Minting Dollar Coins For the sample data from Exercise 1, we get a P-value of 0.0041 when testing the claim that σ < 0.04000 g.
What should we conclude about the null hypothesis?
What should we conclude about the original claim?
What do these results suggest about the new minting process?
Verified step by step guidance1
Step 1: Understand the null hypothesis (H₀) and the alternative hypothesis (H₁). The null hypothesis (H₀) states that σ ≥ 0.04000 g, while the alternative hypothesis (H₁) states that σ < 0.04000 g. This is a one-tailed test for the population standard deviation.
Step 2: Interpret the P-value. The P-value is the probability of observing a test statistic as extreme as, or more extreme than, the one calculated from the sample data, assuming the null hypothesis is true. Here, the P-value is 0.0041.
Step 3: Compare the P-value to the significance level (α). If the P-value is less than the chosen significance level (commonly α = 0.05), we reject the null hypothesis. In this case, 0.0041 < 0.05, so we reject H₀.
Step 4: Conclude about the original claim. Since the null hypothesis is rejected, there is sufficient evidence to support the claim that σ < 0.04000 g. This suggests that the variability in the minting process is less than 0.04000 g.
Step 5: Interpret the results in context. The results suggest that the new minting process is more consistent (less variable) than the threshold of 0.04000 g. This could indicate an improvement in the precision of the minting process.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Null Hypothesis
The null hypothesis is a statement that there is no effect or no difference, and it serves as the default assumption in statistical testing. In this context, it posits that the standard deviation (σ) of the minting process is greater than or equal to 0.04000 g. A low P-value indicates strong evidence against the null hypothesis, suggesting it may be rejected in favor of the alternative hypothesis.
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Step 1: Write Hypotheses
P-value
The P-value is a statistical measure that helps determine the significance of results in hypothesis testing. It represents the probability of observing the data, or something more extreme, assuming the null hypothesis is true. A P-value of 0.0041 indicates a very low probability of obtaining such results if the null hypothesis were correct, leading to the conclusion that the null hypothesis is likely not true.
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Step 3: Get P-Value
Alternative Hypothesis
The alternative hypothesis is the statement that contradicts the null hypothesis, suggesting that there is an effect or a difference. In this scenario, it would claim that the standard deviation (σ) is less than 0.04000 g. The results of the test, particularly the low P-value, provide evidence supporting the alternative hypothesis, indicating that the new minting process may be more precise than previously thought.
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Step 1: Write Hypotheses
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