You are planning a trip to a water park tomorrow and the weather forecaster says there is a 70% chance of rain. Explain what this result means.
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 56m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 17m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - ExcelBonus23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - ExcelBonus28m
- Confidence Intervals for Population Means - ExcelBonus25m
- 8. Sampling Distributions & Confidence Intervals: Proportion2h 10m
- 9. Hypothesis Testing for One Sample5h 8m
- Steps in Hypothesis Testing1h 6m
- Performing Hypothesis Tests: Means1h 4m
- Hypothesis Testing: Means - ExcelBonus42m
- Performing Hypothesis Tests: Proportions37m
- Hypothesis Testing: Proportions - ExcelBonus27m
- Performing Hypothesis Tests: Variance12m
- Critical Values and Rejection Regions28m
- Link Between Confidence Intervals and Hypothesis Testing12m
- Type I & Type II Errors16m
- 10. Hypothesis Testing for Two Samples5h 37m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - ExcelBonus28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - ExcelBonus12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - ExcelBonus9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - ExcelBonus21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - ExcelBonus12m
- Two Variances and F Distribution29m
- Two Variances - Graphing CalculatorBonus16m
- 11. Correlation1h 24m
- 12. Regression3h 33m
- Linear Regression & Least Squares Method26m
- Residuals12m
- Coefficient of Determination12m
- Regression Line Equation and Coefficient of Determination - ExcelBonus8m
- Finding Residuals and Creating Residual Plots - ExcelBonus11m
- Inferences for Slope31m
- Enabling Data Analysis ToolpakBonus1m
- Regression Readout of the Data Analysis Toolpak - ExcelBonus21m
- Prediction Intervals13m
- Prediction Intervals - ExcelBonus19m
- Multiple Regression - ExcelBonus29m
- Quadratic Regression15m
- Quadratic Regression - ExcelBonus10m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA2h 29m
4. Probability
Basic Concepts of Probability
Problem 5.7.26c
Textbook Question
Text Twist
In the game Text Twist, six letters are given and the player must form words of different lengths using those letters. Suppose the letters in a particular game are ENHSIC.
c. The solution to this game has three 6-letter words. To move to the next round, the player must get at least one of the six-letter words. If the player simply guesses, what is the probability of getting one of the six-letter words on the first try?
Verified step by step guidance1
Identify the total number of possible 6-letter arrangements (permutations) that can be formed using the letters ENHSIC. Since all letters are distinct, the total number of permutations is given by the factorial of 6: \$6!$.
Calculate the total number of favorable outcomes. According to the problem, there are exactly three valid 6-letter words that can be formed from these letters. So, the number of favorable outcomes is 3.
Recall that the probability of an event is the ratio of the number of favorable outcomes to the total number of possible outcomes. Therefore, the probability of guessing one of the six-letter words on the first try is \(\frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}\).
Substitute the values into the probability formula: \(\frac{3}{6!}\).
Interpret the result as the chance of randomly selecting one of the three valid six-letter words from all possible permutations of the letters ENHSIC.
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
1mPlay a video:
0 Comments
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Permutation and Counting Outcomes
Permutation refers to the arrangement of all members of a set into some sequence or order. In this problem, the total number of possible 6-letter words formed from the letters ENHSIC is the number of permutations of 6 distinct letters, calculated as 6! = 720. This represents the total number of equally likely outcomes when guessing a word.
Recommended video:
Introduction to Permutations
Favorable Outcomes
Favorable outcomes are the specific outcomes that satisfy the event of interest. Here, the favorable outcomes are the three valid 6-letter words that can be formed from the letters ENHSIC. Identifying the number of favorable outcomes is essential to calculate the probability of guessing one correctly.
Recommended video:
Guided course
The Binomial Experiment
Probability of an Event
Probability measures the likelihood of an event occurring and is calculated as the ratio of favorable outcomes to total possible outcomes. For guessing a six-letter word correctly, the probability is the number of valid six-letter words divided by the total permutations (3/720). This quantifies the chance of success on a random guess.
Recommended video:
Probability of Multiple Independent Events
Related Videos
Related Practice
Textbook Question
29
views
