A travel analyst says that the mean price of a meal for a family of 4 in a resort restaurant is at most $100. A random sample of 33 meal prices for families of 4 has a mean of $110 and a standard deviation of $19. At α=0.01, is there enough evidence to reject the analyst’s claim?
Table of contents
- 1. Intro to Stats and Collecting Data55m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically1h 45m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables2h 33m
- 6. Normal Distribution and Continuous Random Variables1h 38m
- 7. Sampling Distributions & Confidence Intervals: Mean1h 53m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 12m
- 9. Hypothesis Testing for One Sample2h 19m
- 10. Hypothesis Testing for Two Samples3h 22m
- 11. Correlation1h 6m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 20m
- 14. ANOVA1h 0m
9. Hypothesis Testing for One Sample
Performing Hypothesis Tests: Means
Problem 8.3.5
Textbook Question
Finding P-values
In Exercises 5–8, either use technology to find the P-value or use Table A-3 to find a range of values for the P-value. Based on the result, what is the final conclusion?
Weights of Quarters The claim is that weights (grams) of quarters made after 1964 have a mean equal to 5.670 g as required by mint specifications. The sample size is and the test statistic is t = -3.135.

1
Step 1: Identify the null hypothesis (H₀) and the alternative hypothesis (H₁). The null hypothesis is H₀: μ = 5.670 g, which states that the mean weight of quarters is equal to 5.670 g. The alternative hypothesis is H₁: μ ≠ 5.670 g, which indicates a two-tailed test.
Step 2: Determine the degrees of freedom (df) for the t-distribution. The degrees of freedom are calculated as df = n - 1, where n is the sample size. Ensure you know the sample size to compute df.
Step 3: Use the given test statistic t = -3.135 and the degrees of freedom to find the P-value. You can either use statistical software or a t-distribution table (Table A-3). For a two-tailed test, double the area in the tail corresponding to |t| = 3.135.
Step 4: Compare the P-value to the significance level (α). If the P-value is less than α (commonly 0.05), reject the null hypothesis. Otherwise, fail to reject the null hypothesis.
Step 5: Based on the comparison, draw a conclusion. If the null hypothesis is rejected, conclude that there is sufficient evidence to support the claim that the mean weight of quarters is not equal to 5.670 g. If the null hypothesis is not rejected, conclude that there is insufficient evidence to refute the claim.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
P-value
The P-value is a statistical measure that helps determine the significance of results from a hypothesis test. It represents the probability of obtaining test results at least as extreme as the observed results, assuming that the null hypothesis is true. A smaller P-value indicates stronger evidence against the null hypothesis, often leading to its rejection if it falls below a predetermined significance level, such as 0.05.
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Step 3: Get P-Value
Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions about a population based on sample data. It involves formulating two competing hypotheses: the null hypothesis (H0), which represents a default position, and the alternative hypothesis (H1), which represents what we aim to support. The test statistic, such as the t-value in this case, is calculated to assess the evidence against the null hypothesis.
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Step 1: Write Hypotheses
Test Statistic
A test statistic is a standardized value that is calculated from sample data during a hypothesis test. It quantifies the difference between the observed sample statistic and the hypothesized population parameter, scaled by the standard error. In this scenario, the t-statistic of -3.135 indicates how many standard errors the sample mean is away from the hypothesized mean, providing a basis for determining the P-value.
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Step 2: Calculate Test Statistic
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