BackConditional Probability and the Multiplication Rule: Independent and Dependent Events
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Conditional Probability and the Multiplication Rule
Conditional Probability
Conditional probability refers to the probability of an event occurring given that another event has already occurred. This concept is fundamental in understanding how probabilities change when additional information is known.
Notation: The conditional probability of event B given event A is denoted as $P(B|A)$.
Formula: $P(B|A) = \frac{P(A \text{ and } B)}{P(A)}$
Interpretation: The sample space is reduced to only those outcomes where event A has occurred.
Independent and Dependent Events
Events are classified as independent or dependent based on whether the occurrence of one affects the probability of the other.
Independent Events: The occurrence of one event does not affect the probability of the other. For independent events, $P(B|A) = P(B)$.
Dependent Events: The occurrence of one event affects the probability of the other. For dependent events, $P(B|A) \neq P(B)$.
Examples: Classifying Events
Example 1: Tossing a coin and getting a head (A), and then rolling a six-sided die and obtaining a 6 (B). Solution: These events are independent because the outcome of the coin toss does not affect the outcome of the die roll.

Example 2: Driving over 85 miles per hour (A), and then getting in a car accident (B). Solution: These events are dependent because driving at high speed increases the chance of getting in an accident.
The Multiplication Rule
The multiplication rule is used to find the probability that two events, A and B, both occur in sequence.
General Multiplication Rule: $P(A \text{ and } B) = P(A) \cdot P(B|A)$
For Independent Events: $P(A \text{ and } B) = P(A) \cdot P(B)$
This rule can be extended to any number of independent events.
Example: Using the Multiplication Rule to Find Probabilities
Example: Two cards are selected, without replacing the first card, from a standard deck of 52 playing cards. Find the probability of selecting a king and then selecting a queen. Solution: Since the first card is not replaced, the events are dependent.
Probability of first card being a king: $P(K) = \frac{4}{52}$
Probability of second card being a queen given first was a king: $P(Q|K) = \frac{4}{51}$
Combined probability: $P(K \text{ and } Q) = \frac{4}{52} \times \frac{4}{51} = 0.006$
Additional info: The multiplication rule is essential for calculating probabilities in sequences of events, especially when events are not independent (such as drawing cards without replacement).