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Normal Probability Distributions and Their Applications

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Normal Probability Distributions

Standard Normal Distribution

The standard normal distribution is a special case of the normal probability distribution with a mean of 0 and a standard deviation of 1. It is widely used in statistics for calculating probabilities and z-scores.

  • Bell-shaped curve: The graph is symmetric and centered at zero.

  • Mean (μ): 0

  • Standard deviation (σ): 1

  • Total area under the curve: 1 (corresponds to probability 1)

Because the total area under the curve is 1, the area under the curve between two points represents the probability of a value falling within that range.

Standard normal distribution curve with area = 1

z-Scores

A z-score measures how many standard deviations a value is from the mean. Each unit on the z-scale represents one standard deviation. The formula for a z-score is:

  • Unusual events: Typically, z-scores less than -2 or greater than 2 are considered unusual, but the threshold may vary depending on context.

Finding Areas and Probabilities

To find the probability that a value falls within a certain range, use the area under the curve between the corresponding z-scores. Calculators and statistical tables can be used for this purpose. For example, the calculator function normalcdf(L.B., U.B., μ, σ) gives the area (probability) between two bounds.

Example: Bone Density Test

  • Context: Bone density z-scores are normally distributed with μ = 0 and σ = 1.

  • Find the probability of a reading less than 1.27: Use normalcdf(-∞, 1.27, 0, 1).

  • Find the probability of a reading above -1.00: Use normalcdf(-1.00, ∞, 0, 1).

  • Probability of osteopenia (between -1.00 and -2.50): Use normalcdf(-2.50, -1.00, 0, 1).

Finding Probabilities for Given z-Scores

To find the probability for a given z-score, calculate the area under the curve to the left (for less than) or to the right (for greater than) that z-score.

  • Less than z = -1.50: Area to the left of -1.50

  • Greater than z = 2.22: Area to the right of 2.22

  • Between z = -1.20 and z = 1.95: Area between these two z-scores

Finding z-Scores for Given Probabilities

To find the z-score corresponding to a given cumulative probability (area to the left), use the InvNorm function:

  • InvNorm(area, μ, σ): Returns the z-score for the specified area to the left.

Examples:

  • Find the z-score for area = 0.7542

  • Find the z-score for area = 0.2222

  • Find the z-score for the top 40% (area to the left = 0.60)

  • Find the z-score for the top 95% (area to the left = 0.05 for the lower tail, or 0.95 for the upper tail)

Applications of Normal Distributions

Standard vs. Non-Standard Normal Distributions

The standard normal distribution uses μ = 0 and σ = 1. A non-standard normal distribution has any mean μ and standard deviation σ. To use standard normal tables or calculator functions, convert values to z-scores.

Shaded area under normal curve representing probabilityShaded area under normal curve from 0 to z

Example: Tall Clubs International

  • Requirement: Women must be at least 70 inches tall.

  • Given: Heights are normally distributed with μ = 63.8 in, σ = 2.6 in.

  • Find: Percentage of women who meet the requirement (P(X ≥ 70)).

  • Solution: Convert 70 to a z-score, then use normalcdf(70, ∞, 63.8, 2.6).

Example: Water Taxi Load

  • Safe load: 3500 lb; mean passenger weight = 172 lb; σ = 29 lb.

  • Find: Probability a randomly selected man weighs less than 174 lb.

  • Solution: Use normalcdf(-∞, 174, 172, 29).

Example: Aircraft Cabin Height

  • Goal: Find ceiling height so 95% of men can stand without bumping heads.

  • Given: μ = 69.5 in, σ = 2.4 in.

  • Solution: Use InvNorm(0.95, 69.5, 2.4) to find the required height.

Normal curve with mean and standard deviation marked

Example: Newborn Baby Weights

  • Given: μ = 7 lb, σ = 2.5 lb.

  • Find: The 82nd percentile (P82), the weight separating the bottom 82% from the top 18%.

  • Solution: Use InvNorm(0.82, 7, 2.5).

Central Limit Theorem (CLT)

Sampling Distributions and the CLT

The Central Limit Theorem states that the distribution of sample means approaches a normal distribution as the sample size increases, regardless of the population's distribution, provided the samples are independent and identically distributed.

  • Mean of sample means: μx̄ = μ

  • Standard deviation of sample means (standard error):

The z-score formula for sample means is:

To find probabilities for sample means, use normalcdf(L.B., U.B., μ, σ/√n).

Example: Water Taxi with 25 Passengers

  • Safe load: 3500 lb; mean passenger weight = 172 lb; σ = 29 lb; n = 25.

  • Find: Probability that the mean weight of 25 men exceeds 175 lb.

  • Solution: Use the CLT formula for z, then normalcdf(175, ∞, 172, 29/√25).

Normal curve with mean and standard deviation marked for sample means

Example: Elevator Capacity

  • Maximum capacity: 16 passengers, 2500 lb total; mean male weight = 182.9 lb; σ = 40.8 lb.

  • a. Probability one male exceeds 156.25 lb: Use normalcdf(156.25, ∞, 182.9, 40.8).

  • b. Probability mean of 16 males exceeds 156.25 lb: Use normalcdf(156.25, ∞, 182.9, 40.8/√16).

Summary Table: Key Normal Distribution Functions

Function

Purpose

Parameters

normalcdf(L.B., U.B., μ, σ)

Find probability between two values

Lower bound, Upper bound, Mean, Std. Dev.

InvNorm(area, μ, σ)

Find value (or z-score) for a given cumulative probability

Area to left, Mean, Std. Dev.

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