A right triangle kite has a right angle at vertex N, with side KN adjacent to angle K and side NM adjacent to angle M. If angle K is and the hypotenuse KM is units, what are the lengths of sides KN and NM? KN = units, NM = units
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
2. Trigonometric Functions on Right Triangles
Solving Right Triangles
Struggling with Trigonometry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Given a right triangle QSU with side lengths units, units, and as the hypotenuse, what is the perimeter of triangle QSU?
A
units
B
units
C
units
D
units
Verified step by step guidance1
Identify the sides of the right triangle QSU: QS = 5 units, SU = 12 units, and UQ is the hypotenuse.
Recall the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse equals the sum of the squares of the other two sides: \(UQ^2 = QS^2 + SU^2\).
Calculate the length of the hypotenuse UQ by substituting the known side lengths into the Pythagorean theorem: \(UQ^2 = 5^2 + 12^2\).
Simplify the expression to find \(UQ^2 = 25 + 144\), then take the square root of both sides to find \(UQ = \sqrt{169}\).
Once you have the length of UQ, find the perimeter of triangle QSU by adding all three side lengths: \(Perimeter = QS + SU + UQ\).
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