Which statement proves that triangle is an isosceles right triangle?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
2. Trigonometric Functions on Right Triangles
Solving Right Triangles
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
A right triangle has a base of units and the angle opposite the height is . What is the height of the triangle?
A
units
B
units
C
units
D
units
Verified step by step guidance1
Identify the given elements in the right triangle: the base length is 68 units, and the angle opposite the height (which is the side we want to find) is 15 degrees.
Recall that in a right triangle, the sine of an angle is the ratio of the length of the side opposite the angle to the hypotenuse. However, here we have the base (adjacent side) and want the height (opposite side), so we can use the tangent function instead.
Write the tangent function for the 15° angle: \(\tan(15^\circ) = \frac{\text{height}}{\text{base}}\).
Substitute the known base length into the equation: \(\tan(15^\circ) = \frac{\text{height}}{68}\).
Solve for the height by multiplying both sides by 68: \(\text{height} = 68 \times \tan(15^\circ)\).
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Solving Right Triangles practice set

