The point (π/4, 1) lies on the graph of y = tan x. Therefore, the point _______ lies on the graph of y = tan⁻¹ x.
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Understand the problem: The point \( \left( \frac{\pi}{4}, 1 \right) \) lies on the graph of \( y = \tan x \). This means that when \( x = \frac{\pi}{4} \), \( y = 1 \).
Recall the definition of the inverse tangent function \( y = \tan^{-1} x \): it reverses the roles of \( x \) and \( y \) from the original function \( y = \tan x \).
Since \( y = \tan x \) passes through \( \left( \frac{\pi}{4}, 1 \right) \), the inverse function \( y = \tan^{-1} x \) will pass through the point where the coordinates are swapped, i.e., \( (1, \frac{\pi}{4}) \).
Therefore, the point \( (1, \frac{\pi}{4}) \) lies on the graph of \( y = \tan^{-1} x \).
This step completes the understanding that the inverse function's graph is the reflection of the original function's graph across the line \( y = x \).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Inverse Trigonometric Functions
Inverse trigonometric functions, such as arctan or tan⁻¹, reverse the effect of their corresponding trigonometric functions. For y = tan⁻¹ x, the output is the angle whose tangent is x, effectively swapping the roles of input and output compared to y = tan x.
If a point (a, b) lies on the graph of a function f, then the point (b, a) lies on the graph of its inverse function f⁻¹. This means the coordinates are reversed, reflecting the inverse relationship between the two functions.
The tangent function, tan x, maps angles to real numbers and is periodic with period π. Its inverse, arctan, maps real numbers back to angles within the principal range (-π/2, π/2), ensuring a one-to-one correspondence necessary for defining the inverse.