In Exercises 35–38, find the exact value of the following under the given conditions: d. sin 2α sin α = 3/5, 0 < α < 𝝅/2, and sin β = 12/13, 𝝅/2 < β < 𝝅.
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Identify the given information: \(\sin \alpha = \frac{3}{5}\) with \(0 < \alpha < \frac{\pi}{2}\), and \(\sin \beta = \frac{12}{13}\) with \(\frac{\pi}{2} < \beta < \pi\).
Recall the double-angle identity for sine: \(\sin 2\alpha = 2 \sin \alpha \cos \alpha\).
Since \(\sin \alpha\) is known, find \(\cos \alpha\) using the Pythagorean identity: \(\cos \alpha = \sqrt{1 - \sin^2 \alpha}\), considering the quadrant of \(\alpha\) to determine the sign.
Calculate \(\cos \alpha\) by substituting \(\sin \alpha = \frac{3}{5}\) into the identity: \(\cos \alpha = \sqrt{1 - \left(\frac{3}{5}\right)^2}\).
Substitute \(\sin \alpha\) and \(\cos \alpha\) into the double-angle formula \(\sin 2\alpha = 2 \sin \alpha \cos \alpha\) to express \(\sin 2\alpha\) exactly.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Double-Angle Identity for Sine
The double-angle identity states that sin(2α) = 2 sin(α) cos(α). This formula allows you to find the sine of twice an angle using the sine and cosine of the original angle. Knowing sin(α) and the quadrant of α helps determine cos(α) and thus compute sin(2α) exactly.
Given sin(α), the cosine can be found using cos²(α) = 1 - sin²(α). The sign of cos(α) depends on the quadrant where α lies. Since 0 < α < π/2 (first quadrant), cos(α) is positive, enabling exact calculation of cos(α) from sin(α).
Understanding Angle Quadrants and Their Significance
The quadrant of an angle determines the signs of its sine and cosine values. For example, if 0 < α < π/2, both sine and cosine are positive. For β in (π/2, π), sine is positive but cosine is negative. This knowledge is essential for correctly determining trigonometric values and applying identities.