Given the following vector, $\mathbf{v}$, obtain the unit vector that aligns with the direction of $\mathbf{v}$.
$\mathbf{v}=-\mathbf{i}-\sqrt3\mathbf{j}$

$-\frac14\mathbf{i}+\frac{\sqrt3}{4}\mathbf{j}$

$-\frac12\mathbf{i}-\frac{\sqrt3}{2}\mathbf{j}$

$-\frac12\mathbf{i}+\frac{\sqrt3}{2}\mathbf{j}$

$-\frac14\mathbf{i}-\frac{\sqrt3}{4}\mathbf{j}$