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Multiple Choice
Evaluate the triple integral of over the part of the ball defined by that lies in the first octant.
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Verified step by step guidance
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Step 1: Recognize that the problem involves evaluating a triple integral over a region defined by the inequality x² + y² + z² ≤ 8, which represents a ball of radius √8 centered at the origin. The region is restricted to the first octant, where x, y, and z are all non-negative.
Step 2: Convert the integral into spherical coordinates for simplicity. In spherical coordinates, x = ρsin(φ)cos(θ), y = ρsin(φ)sin(θ), and z = ρcos(φ), where ρ is the radial distance, φ is the polar angle, and θ is the azimuthal angle. The volume element dV becomes ρ²sin(φ)dρdφdθ.
Step 3: Set up the limits of integration. In the first octant, θ ranges from 0 to π/2, φ ranges from 0 to π/2, and ρ ranges from 0 to √8 (the radius of the ball). The integrand is 1, as specified in the problem.
Step 4: Write the integral in spherical coordinates: ∫∫∫ ρ²sin(φ)dρdφdθ, with the limits of integration being ρ ∈ [0, √8], φ ∈ [0, π/2], and θ ∈ [0, π/2].
Step 5: Evaluate the integral step by step. First, integrate with respect to ρ, then φ, and finally θ, applying the limits of integration at each step. This will yield the volume of the region in the first octant.