Evaluate the integral:
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
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- Introduction to Trigonometric Functions38m
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- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
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- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
0. Functions
Introduction to Functions
Multiple Choice
Evaluate the line integral of the vector field along the path given by for .
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Verified step by step guidance1
Step 1: Understand the problem. You are tasked with evaluating the line integral of the vector field F(x, y) = (2x, 3y) along the path C defined by r(t) = (t, t^2) for t in the interval [0, 1]. The line integral is given by ∫C F · dr, where F · dr represents the dot product of the vector field F and the differential displacement vector dr.
Step 2: Compute dr. The path C is parameterized by r(t) = (t, t^2). To find dr, differentiate r(t) with respect to t. This gives dr = (dx/dt, dy/dt) dt = (1, 2t) dt.
Step 3: Substitute r(t) into F(x, y). The vector field F(x, y) = (2x, 3y) becomes F(r(t)) = (2t, 3t^2) when x = t and y = t^2.
Step 4: Compute the dot product F · dr. Substitute F(r(t)) = (2t, 3t^2) and dr = (1, 2t) dt into the dot product formula. This gives F · dr = (2t)(1) + (3t^2)(2t) dt = 2t + 6t^3 dt.
Step 5: Set up the integral. The line integral ∫C F · dr becomes ∫[0,1] (2t + 6t^3) dt. Evaluate this integral by finding the antiderivative of 2t + 6t^3 and then applying the limits of integration from t = 0 to t = 1.
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