What is the slope of the tangent line to the curve at the point ?
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
2. Intro to Derivatives
Tangent Lines and Derivatives
Multiple Choice
Find the equation of the tangent line to the curve at the point .
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Verified step by step guidance1
Step 1: Recall that the equation of a tangent line to a curve at a given point is given by y - y₁ = m(x - x₁), where m is the slope of the tangent line and (x₁, y₁) is the point of tangency.
Step 2: To find the slope m, calculate the derivative of the given function y = sin(x) + cos(x). The derivative, y', represents the slope of the tangent line at any point on the curve. Using differentiation rules: y' = d/dx[sin(x)] + d/dx[cos(x)] = cos(x) - sin(x).
Step 3: Evaluate the derivative at the given point (0, 1). Substitute x = 0 into y' = cos(x) - sin(x). This gives m = cos(0) - sin(0).
Step 4: Substitute the slope m and the point (x₁, y₁) = (0, 1) into the tangent line equation y - y₁ = m(x - x₁). This becomes y - 1 = m(x - 0).
Step 5: Simplify the equation to express the tangent line in slope-intercept form (y = mx + b). Replace m with the evaluated slope from Step 3 and simplify further to obtain the final equation of the tangent line.
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