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Multiple Choice
What is the slope of the tangent line to the curve at the point ?
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Step 1: Recognize that the problem involves finding the slope of the tangent line to the curve x^2 + y^2 = 2 at the point (1, 1). To do this, we need to use implicit differentiation since the equation involves both x and y.
Step 2: Differentiate both sides of the equation x^2 + y^2 = 2 with respect to x. Remember that y is a function of x, so when differentiating y^2, apply the chain rule. The derivative of x^2 is 2x, and the derivative of y^2 is 2y * (dy/dx). The result is: .
Step 3: Solve for dy/dx, which represents the slope of the tangent line. Rearrange the equation to isolate dy/dx: .
Step 4: Substitute the given point (1, 1) into the expression for dy/dx. At this point, x = 1 and y = 1, so substitute these values into .
Step 5: Simplify the expression after substitution to determine the slope of the tangent line. The slope is .