What is the slope of the tangent line to the curve at the point ?
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
2. Intro to Derivatives
Tangent Lines and Derivatives
Multiple Choice
Find an equation of the tangent plane to the surface at the point .
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Verified step by step guidance1
Step 1: Recall the general formula for the equation of the tangent plane to a surface z = f(x, y) at a point (x₀, y₀, z₀). The formula is given by: z - z₀ = fₓ(x₀, y₀)(x - x₀) + fᵧ(x₀, y₀)(y - y₀), where fₓ and fᵧ are the partial derivatives of f with respect to x and y, respectively.
Step 2: Compute the partial derivative of the given surface z = x² + y² with respect to x. This gives fₓ(x, y) = ∂/∂x(x² + y²) = 2x.
Step 3: Compute the partial derivative of the given surface z = x² + y² with respect to y. This gives fᵧ(x, y) = ∂/∂y(x² + y²) = 2y.
Step 4: Evaluate the partial derivatives at the given point (1, 2). For fₓ(1, 2), substitute x = 1 and y = 2 into fₓ(x, y) = 2x, resulting in fₓ(1, 2) = 2(1) = 2. Similarly, for fᵧ(1, 2), substitute x = 1 and y = 2 into fᵧ(x, y) = 2y, resulting in fᵧ(1, 2) = 2(2) = 4.
Step 5: Substitute the values x₀ = 1, y₀ = 2, z₀ = 5, fₓ(1, 2) = 2, and fᵧ(1, 2) = 4 into the tangent plane formula z - z₀ = fₓ(x₀, y₀)(x - x₀) + fᵧ(x₀, y₀)(y - y₀). Simplify the equation to find the tangent plane: z = 2(x - 1) + 4(y - 2) + 5.
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