Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Given the parametric equations and for , what is the area enclosed by the curve and the y-axis?
A
B
C
D
Verified step by step guidance
1
Step 1: Recall the formula for the area enclosed by a parametric curve and the y-axis. The area is given by \( A = \int y \cdot \frac{dx}{dt} \, dt \), where \( x \) and \( y \) are expressed in terms of the parameter \( t \).
Step 2: Differentiate \( x = t^2 - 3t \) with respect to \( t \) to find \( \frac{dx}{dt} \). Using the power rule, \( \frac{dx}{dt} = 2t - 3 \).
Step 3: Substitute \( y = t \) and \( \frac{dx}{dt} = 2t - 3 \) into the area formula. The integral becomes \( A = \int_{0}^{3} t \cdot (2t - 3) \, dt \).
Step 4: Expand the integrand \( t \cdot (2t - 3) \) to simplify the expression. This gives \( A = \int_{0}^{3} (2t^2 - 3t) \, dt \).
Step 5: Set up the integral for evaluation. Break it into two parts: \( A = \int_{0}^{3} 2t^2 \, dt - \int_{0}^{3} 3t \, dt \). Evaluate each term separately to find the total area.