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Multiple Choice
Evaluate the definite integral: .
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Verified step by step guidance
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Step 1: Recognize that the integral \( \int_1^2 w^2 \ln(w) \, dw \) involves a product of functions \( w^2 \) and \( \ln(w) \). This suggests using integration by parts, which is based on the formula \( \int u \, dv = uv - \int v \, du \).
Step 2: Choose \( u = \ln(w) \) (since its derivative simplifies) and \( dv = w^2 \, dw \) (since its integral is straightforward). Compute \( du = \frac{1}{w} \, dw \) and \( v = \frac{w^3}{3} \).
Step 3: Apply the integration by parts formula: \( \int_1^2 w^2 \ln(w) \, dw = \left[ \frac{w^3}{3} \ln(w) \right]_1^2 - \int_1^2 \frac{w^3}{3} \cdot \frac{1}{w} \, dw \). Simplify the second integral to \( \int_1^2 \frac{w^2}{3} \, dw \).
Step 4: Evaluate the first term \( \left[ \frac{w^3}{3} \ln(w) \right]_1^2 \) by substituting the limits \( w = 2 \) and \( w = 1 \). Then, compute the second term \( \int_1^2 \frac{w^2}{3} \, dw \) by finding the antiderivative of \( \frac{w^2}{3} \), which is \( \frac{w^3}{9} \), and substituting the limits.
Step 5: Combine the results from the first term and the second term to express the final value of the definite integral. Compare the result to the given answer choices to identify the correct one.