Textbook Question
Velocity to position Given the following velocity functions of an object moving along a line, find the position function with the given initial position.
v(t) = 6t² + 4t - 10; s(0) = 0
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7. Antiderivatives & Indefinite Integrals
Initial Value Problems
2:10 minutesProblem 4.R.105
Textbook Question
104–107. Functions from derivatives Find the function f with the following properties.
ƒ'(t) = sin t + 2t; ƒ(0) = 5
Verified step by step guidance1
Step 1: Recognize that the problem involves finding the original function ƒ(t) given its derivative ƒ'(t) = sin(t) + 2t and an initial condition ƒ(0) = 5.
Step 2: To find ƒ(t), integrate the derivative ƒ'(t). Start by breaking ƒ'(t) into two terms: sin(t) and 2t. The integral of ƒ'(t) will be the sum of the integrals of these terms.
Step 3: Compute the integral of sin(t). Recall that the integral of sin(t) with respect to t is -cos(t).
Step 4: Compute the integral of 2t. Recall that the integral of t^n (where n = 1) is t^(n+1)/(n+1). Therefore, the integral of 2t is t^2.
Step 5: Combine the results from the integration: ƒ(t) = -cos(t) + t^2 + C, where C is the constant of integration. Use the initial condition ƒ(0) = 5 to solve for C by substituting t = 0 into ƒ(t).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Derivatives
A derivative represents the rate of change of a function with respect to its variable. It provides information about the function's slope at any given point. In this context, ƒ'(t) = sin t + 2t indicates how the function f changes as t varies, which is essential for finding the original function f.
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Derivatives
Integration
Integration is the process of finding the antiderivative of a function, essentially reversing differentiation. To find the function f from its derivative ƒ'(t), we need to integrate the expression sin t + 2t. This will yield a family of functions, which we can then refine using initial conditions.
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Initial Conditions
Initial conditions are specific values that help determine a unique solution to a differential equation or an integral. In this case, the condition ƒ(0) = 5 allows us to find the constant of integration after performing the integration, ensuring that the function f satisfies the given requirement at t = 0.
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