Calculate the first, second, and third derivatives of the function $k\left(x\right)=2x^6+4x^5+9x^3$.

$k^{\prime }\left(x\right)=12x^5+20x^4+27x^2$

$k^{\prime }$${}^{\prime }\left(x\right)=12x^4+20x^3+27x$

$k^{\prime }$${}^{\prime }$${}^{\prime }\left(x\right)=$ $12x^3+20x^2+27$

$k^{\prime }\left(x\right)=12x^5+20x^4+27x^2$

$k^{\prime }$${}^{\prime }\left(x\right)=12x^4+20x^3+27x$

$k^{\prime }$${}^{\prime }$${}^{\prime }\left(x\right)=$ $48x^3+60x^2+27$

$k^{\prime }\left(x\right)=12x^5+20x^4+27x^2$

$k^{\prime }$${}^{\prime }\left(x\right)=60x^4+80x^3+54x$

$k^{\prime }$${}^{\prime }$${}^{\prime }\left(x\right)=$ $60x^3+80x^2+54$

$k^{\prime }\left(x\right)=12x^5+20x^4+27x^2$

$k^{\prime }$${}^{\prime }\left(x\right)=60x^4+80x^3+54x$

$k^{\prime }$${}^{\prime }$${}^{\prime }\left(x\right)=$ $240x^3+240x^2+54$