find-the-second-derivative-of-fx2sinx3cosxfleftxright2sin-x-3cos-x-with-respect-

Question

Find the second derivative of f(x)=2sin⁡x−3cos⁡xf\left(x\right)=2\sin x-3\cos x with respect to xx.

Accepted Answer

d2dx2(f(x))=−2sin⁡x+3cos⁡x\frac{$$d^2$$}{$$dx^2$$}\left(f\left(x\right)\right)=-2\sin x+3\cos x

Answer

d2dx2(f(x))=2sin⁡x−3cos⁡x\frac{$$d^2$$}{$$dx^2$$}\left(f\left(x\right)\right)=2\sin x-3\cos x

Answer

d2dx2(f(x))=−2sin⁡x−3cos⁡x\frac{$$d^2$$}{$$dx^2$$}\left(f\left(x\right)\right)=-2\sin x-3\cos x

Answer

d2dx2(f(x))=2sin⁡x+3cos⁡x\frac{$$d^2$$}{$$dx^2$$}\left(f\left(x\right)\right)=2\sin x+3\cos x

Find the second derivative of f(x)=2sinx−3cosxf\(\left\)(x\(\right\))=2\(\sin\) x-3\(\cos\) x with respect to xx.