Given functions f and g, (g∘ƒ)(x) and its domain. ƒ(x)=1/(x-2), g(x)=1/x
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Identify the composition of functions (g \(\circ\) f)(x), which means g(f(x)). This involves substituting the entire function f(x) into g(x).
Write down the given functions explicitly: \( f(x) = \frac{1}{x-2} \) and \( g(x) = \frac{1}{x} \).
Substitute \( f(x) \) into \( g(x) \) to get \( (g \circ f)(x) = g\left( \frac{1}{x-2} \right) = \frac{1}{\frac{1}{x-2}} \).
Simplify the expression \( \frac{1}{\frac{1}{x-2}} \) by multiplying numerator and denominator appropriately to find the simplified form of \( (g \circ f)(x) \).
Determine the domain of \( (g \circ f)(x) \) by considering the restrictions from both \( f(x) \) and \( g(x) \): exclude values where \( x-2=0 \) (to avoid division by zero in \( f(x) \)) and where \( f(x) = 0 \) (to avoid division by zero in \( g(f(x)) \)).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Function Composition
Function composition involves applying one function to the result of another, denoted as (g∘f)(x) = g(f(x)). It requires substituting the entire output of f(x) into g, creating a new function that combines both operations.
The domain of a function is the set of all input values for which the function is defined. When composing functions, the domain of (g∘f)(x) includes all x-values in the domain of f for which f(x) is in the domain of g.
Rational functions like f(x) = 1/(x-2) and g(x) = 1/x have restrictions where denominators cannot be zero. Identifying these values is essential to determine the domain and ensure the function is defined.