Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Which of the following statements correctly describes the Lewis dot structure of neutral SBr2?
A
Sulfur is the central atom, bonded to two bromine atoms, with two lone pairs on sulfur.
B
Sulfur is the central atom, bonded to two bromine atoms, with no lone pairs on sulfur.
C
Bromine is the central atom, bonded to two sulfur atoms, with two lone pairs on bromine.
D
Sulfur is the central atom, bonded to two bromine atoms, with one lone pair on sulfur.
Verified step by step guidance
1
Step 1: Determine the total number of valence electrons for the molecule SBr2. Sulfur (S) is in group 16 and has 6 valence electrons, and each bromine (Br) atom is in group 17 with 7 valence electrons. Calculate the total by adding these together: $6 + 2 \times 7$.
Step 2: Identify the central atom. Generally, the least electronegative atom (excluding hydrogen) is the central atom. Between sulfur and bromine, sulfur is less electronegative, so sulfur will be the central atom bonded to two bromine atoms.
Step 3: Draw single bonds between the central sulfur atom and each bromine atom. Each single bond represents 2 electrons shared between atoms, so subtract these bonding electrons from the total valence electrons.
Step 4: Distribute the remaining electrons as lone pairs to satisfy the octet rule for each atom. Start by completing the octets of the outer atoms (bromine), then place any leftover electrons on the central atom (sulfur).
Step 5: Count the lone pairs on the central sulfur atom after distributing electrons. This will help determine which statement correctly describes the Lewis structure, focusing on the number of lone pairs on sulfur.