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Ch.19 - Free Energy & Thermodynamics
Tro - Chemistry: A Molecular Approach 6th Edition
Tro6th EditionChemistry: A Molecular ApproachISBN: 9780137832217Not the one you use?Change textbook
All textbooksTro 6th EditionCh.19 - Free Energy & ThermodynamicsProblem 100
Chapter 19, Problem 100

The values of ΔG°f for the hydrogen halides become less negative with increasing atomic number. The ΔG°f of HI is slightly positive. However, the trend in ΔS°f is to become more positive with increasing atomic number. Explain.

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Understand the terms: ΔGf° represents the standard Gibbs free energy of formation, which indicates the spontaneity of a reaction at standard conditions. ΔSf° represents the standard entropy of formation, which measures the disorder or randomness in the system during the formation of a compound.
Recognize the trend in ΔGf°: As the atomic number of the halogen in hydrogen halides (HX) increases, the ΔGf° values become less negative, indicating that the reactions are less spontaneous. For HI, the ΔGf° is slightly positive, suggesting that the reaction is non-spontaneous under standard conditions.
Analyze the trend in ΔSf°: The entropy of formation, ΔSf°, becomes more positive with increasing atomic number. This indicates that the disorder in the system increases as the size of the halogen atom increases.
Relate ΔGf° and ΔSf° with the atomic size: Larger atoms like iodine in HI have more electrons and electron shells, which can contribute to greater molecular complexity and randomness, leading to higher entropy values.
Combine the concepts: The increasing entropy (ΔSf°) with atomic number can contribute to the less negative (or more positive) ΔGf° values. According to the Gibbs free energy equation ΔG = ΔH - TΔS, a higher entropy value can offset changes in enthalpy (ΔH), influencing the spontaneity of the reaction.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Gibbs Free Energy (ΔGf°)

Gibbs Free Energy (ΔGf°) is a thermodynamic potential that measures the maximum reversible work obtainable from a thermodynamic system at constant temperature and pressure. A negative ΔGf° indicates that a substance is thermodynamically stable and favors formation, while a positive value suggests instability. The trend of ΔGf° becoming less negative for hydrogen halides as atomic number increases reflects the increasing stability of heavier halides.
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Entropy (ΔSf°)

Entropy (ΔSf°) is a measure of the disorder or randomness in a system. In the context of hydrogen halides, the trend of ΔSf° becoming more positive with increasing atomic number indicates that the heavier halides have greater molecular complexity and thus higher degrees of freedom, leading to increased disorder. This increase in entropy contributes to the overall thermodynamic stability of the heavier halides despite their less negative Gibbs Free Energy.
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Trends in Halides

The trends in the properties of hydrogen halides, such as ΔGf° and ΔSf°, are influenced by atomic size and bond strength. As the atomic number increases from fluorine to iodine, the bond lengths increase, and bond strengths generally decrease, affecting the stability and formation energies of the compounds. This interplay between bond characteristics and molecular complexity explains the observed trends in Gibbs Free Energy and entropy for these halides.
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Related Practice
Textbook Question

Indicate and explain the sign of ΔSuniv for each process. a. 2 H2(g) + O2(g) → 2 H2O (l) at 298 K.

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Textbook Question

All the oxides of nitrogen have positive values of ΔG°f at 298 K, but only one common oxide of nitrogen has a positive ΔS°f. Identify that oxide of nitrogen without reference to thermodynamic data and explain.

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Textbook Question

These reactions are important in catalytic converters in automobiles. Calculate ΔG° for each at 298 K. Predict the effect of increasing temperature on the magnitude of ΔG°.

a. 2 CO(g) + 2 NO(g) → N2(g) + 2 CO2(g)

b. 5 H2(g) + 2 NO(g) → 2 NH3(g) + 2 H2O(g)

c. 2 H2(g) + 2 NO(g) → N2(g) + 2 H2O(g)

d. 2 NH3(g) + 2 O2(g) → N2O(g) + 3 H2O(g)

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