Contrast the structure of SINE and LINE DNA sequences. Why are LINEs referred to as retrotransposons?
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
16. Transposable Elements
Transposable Elements in Eukaryotes
Problem 23
Textbook Question
The human genome contains approximately 106 copies of an Alu sequence, one of the best-studied classes of short interspersed elements (SINEs), per haploid genome. Individual Alu units share a 282-nucleotide consensus sequence followed by a 3'-adenine-rich tail region [Schmid (1998)]. Given that there are approximately 3 x 109 base pairs per human haploid genome, about how many base pairs are spaced between each Alu sequence?

1
Step 1: Understand the problem. The question asks us to calculate the average number of base pairs spaced between each Alu sequence in the human haploid genome. We are given the total number of base pairs in the haploid genome (3 x 10⁹ base pairs) and the total number of Alu sequences (10⁶ copies).
Step 2: Set up the calculation. To find the average spacing between Alu sequences, divide the total number of base pairs in the haploid genome by the total number of Alu sequences. This will give the average number of base pairs between each Alu sequence.
Step 3: Write the formula for the calculation. The formula is:
Step 4: Simplify the formula. Divide the numerator (3 x 10⁹) by the denominator (10⁶). This will yield the average spacing in base pairs between Alu sequences.
Step 5: Interpret the result. The final value represents the average number of base pairs spaced between each Alu sequence in the human haploid genome. This spacing is an approximation based on the given data.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Alu Sequences
Alu sequences are a type of short interspersed nuclear element (SINE) found in the human genome. They are approximately 300 base pairs long and are derived from the 7SL RNA gene. Alu elements are notable for their ability to replicate and insert themselves into various locations within the genome, contributing to genetic diversity and evolution.
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Human Genome Size
The human genome consists of about 3 billion base pairs organized into 23 pairs of chromosomes. This vast amount of genetic material encodes the instructions for building and maintaining the human body. Understanding the total number of base pairs is crucial for calculating the spacing between repetitive elements like Alu sequences.
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Human Genome Composition
Calculation of Spacing
To determine the average spacing between Alu sequences, one can divide the total number of base pairs in the genome by the number of Alu copies present. This calculation provides insight into how densely these elements are distributed throughout the genome, which can have implications for gene regulation and genomic stability.
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