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Multiple Choice
Aspirin also known as acetylsalicylic acid possesses an ester group that is formed from the reaction between ethanoic acid and salicylic acid. Determine the structure of aspirin after the condensation between ethanoic acid and salicylic acid.
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Verified step by step guidance
1
Identify the functional groups involved in the reaction: Ethanoic acid has a carboxylic acid group (-COOH) and salicylic acid has both a carboxylic acid group and a phenolic hydroxyl group (-OH).
Recognize that the reaction is a condensation reaction, specifically an esterification, where the carboxylic acid group of ethanoic acid reacts with the phenolic hydroxyl group of salicylic acid.
In the esterification process, the hydroxyl group (-OH) from the carboxylic acid of ethanoic acid and the hydrogen atom from the phenolic hydroxyl group of salicylic acid are removed to form water (H2O).
The remaining oxygen from the phenolic hydroxyl group of salicylic acid forms a bond with the carbonyl carbon of the ethanoic acid, resulting in the formation of an ester linkage.
The final structure of aspirin (acetylsalicylic acid) will have an ester linkage between the acetyl group (from ethanoic acid) and the salicylic acid, with the structure: C6H4(OCOCH3)COOH.