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Multiple Choice
Find the least common denominators of the rational expressions:
A
(x+3)(x−3)(x+2)(x−1)
B
(x+3)(x−3)2(x+2)
C
(x−3)(x−3)2(x−2)
D
(x+3)(x−3)(x+2)(x+1)
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Verified step by step guidance
1
Start by factoring each denominator completely to identify their prime factors. For the first denominator \(x^2 - 9\), recognize it as a difference of squares and factor it as \(\left(x+3\right)\left(x-3\right)\).
Next, factor the second denominator \(x^2 - x - 6\). Find two numbers that multiply to \(-6\) and add to \(-1\). This factors as \(\left(x-3\right)\left(x+2\right)\).
Then, factor the third denominator \(x^2 - 4x + 3\). Find two numbers that multiply to \$3\( and add to \)-4$. This factors as \(\left(x-3\right)\left(x-1\right)\).
To find the least common denominator (LCD), take each distinct factor from all denominators, using the highest power of each factor that appears. Here, the factors are \(\left(x+3\right)\), \(\left(x-3\right)\), \(\left(x+2\right)\), and \(\left(x-1\right)\). Note that \(\left(x-3\right)\) appears in all denominators but only to the first power, so include it once.
Multiply these factors together to write the LCD as \(\left(x+3\right)\left(x-3\right)\left(x+2\right)\left(x-1\right)\). This expression represents the least common denominator for the given rational expressions.