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Multiple Choice
Solve and graph the following absolute value inequalities. Express the solution in interval notation. (A)
A
[−3,−2]
B
(−3,−2)
C
[2,3]
D
(2,3)
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Verified step by step guidance
1
Start with the given inequality involving the absolute value: \(\left|\frac{2x - 5}{3}\right| \leq \frac{1}{3}\).
Recall that for any expression \(A\), the inequality \(|A| \leq B\) (where \(B \geq 0\)) is equivalent to \(-B \leq A \leq B\). Apply this to get: \(-\frac{1}{3} \leq \frac{2x - 5}{3} \leq \frac{1}{3}\).
Multiply all parts of the inequality by 3 to eliminate the denominator, remembering that multiplying by a positive number does not change the inequality signs: \(-1 \leq 2x - 5 \leq 1\).
Next, isolate the term with \(x\) by adding 5 to all parts: \(-1 + 5 \leq 2x \leq 1 + 5\), which simplifies to \(4 \leq 2x \leq 6\).
Finally, divide all parts by 2 to solve for \(x\): \(\frac{4}{2} \leq x \leq \frac{6}{2}\), giving the solution interval for \(x\). Express this solution in interval notation and then graph it on a number line.