10. Quadratic Equations and Functions

The Square Root Property

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Multiple Choice

Solve each quadratic equation using the square root property.
$2 y squared equals 54$

$y=\pm9$

$y=\pm3\sqrt3$

$y=27$

$y=\pm\sqrt3$

Verified step by step guidance

Start with the given quadratic equation: \$2y^2 = 54$.

Isolate the $y^2$ term by dividing both sides of the equation by 2: $y^2 = \frac{54}{2}$.

Simplify the right side to get $y^2 = 27$.

Apply the square root property, which states that if $y^2 = k$, then $y = \pm \sqrt{k}$. So, write $y = \pm \sqrt{27}$.

Simplify the square root by factoring 27 into \$9 \times 3$, then take the square root of 9 out of the radical: $y = \pm 3\sqrt{3}$.

Master Using The Square Root Property with a bite sized video explanation from Patrick Ford

Solve each quadratic equation using the square root property.2y2=542y^2=54