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Multiple Choice
When monosaccharides form cyclic hemiacetals, which type of molecule is released during the linkage process?
A
Carbon dioxide
B
C
Methane
D
O2
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Verified step by step guidance
1
Understand that monosaccharides can form cyclic structures through a reaction between the hydroxyl group and the carbonyl group within the same molecule, resulting in a hemiacetal formation.
Recognize that during the formation of a cyclic hemiacetal, a new bond is formed between the carbonyl carbon and the oxygen of the hydroxyl group, creating a ring structure.
Identify that this process involves the removal of a small molecule as a byproduct of the reaction.
Recall that in organic chemistry, the formation of acetals and hemiacetals typically involves the release of a water molecule (H₂O) as the hydroxyl group (OH) and a hydrogen atom (H) from the carbonyl group combine.
Conclude that the molecule released during the formation of cyclic hemiacetals from monosaccharides is water (H₂O), as it is a common byproduct in such condensation reactions.