Textbook Question
Two bromoethers are obtained from the reaction of the following alkyl dihalide with methanol. Draw the structures of the ethers.
1250
views
Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
Not the one you use?Change textbookSelect a different textbook
Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
All textbooks
Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblem 111a,b
Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblem 111a,bChapter 10, Problem 111a,b
Draw the elimination products for each of the following E2 reactions; if the products can exist as stereoisomers, indicate which stereoisomers are obtained.
a. (2S,3S)-2-chloro-3-methylpentane + high concentration of CH3O−
b. (2S,3R)-2-chloro-3-methylpentane + high concentration of CH3O−
Verified step by step guidance1
Step 1: Understand the E2 elimination mechanism. E2 (bimolecular elimination) is a one-step reaction where a base abstracts a proton (β-hydrogen) from the β-carbon, and the leaving group (e.g., Cl⁻) departs simultaneously, forming a double bond. The reaction requires an anti-periplanar geometry between the β-hydrogen and the leaving group.
Step 2: Analyze the structure of (2S, 3S)-2-chloro-3-methylpentane. Draw the molecule in its correct stereochemical configuration. Identify the β-hydrogens on the β-carbons adjacent to the carbon bearing the leaving group (Cl). Ensure you consider the anti-periplanar geometry for elimination.
Step 3: Determine the possible elimination products for (2S, 3S)-2-chloro-3-methylpentane. The double bond will form between the α-carbon (carbon bearing the leaving group) and the β-carbon. Check if the products can exist as stereoisomers (E/Z isomers) based on the substituents around the double bond.
Step 4: Repeat the process for (2S, 3R)-2-chloro-3-methylpentane. Draw the molecule in its correct stereochemical configuration. Identify the β-hydrogens and ensure the anti-periplanar geometry is satisfied for elimination. Predict the possible elimination products and check for stereoisomers.
Step 5: Summarize the elimination products for both (2S, 3S)-2-chloro-3-methylpentane and (2S, 3R)-2-chloro-3-methylpentane. Indicate the stereoisomers (E/Z) obtained for each case, if applicable. Note that the stereochemistry of the starting material influences the stereochemistry of the products due to the anti-periplanar requirement.
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
7mWas this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
E2 Mechanism
The E2 mechanism is a type of elimination reaction where a base removes a proton from a β-carbon, leading to the simultaneous departure of a leaving group from the α-carbon. This concerted process results in the formation of a double bond. Understanding the stereochemistry of the starting material is crucial, as it influences the stereochemical outcome of the elimination products.
Recommended video:
Guided course
09:36
Drawing the E2 Mechanism.
Stereoisomerism
Stereoisomerism refers to the phenomenon where compounds have the same molecular formula and connectivity but differ in the spatial arrangement of atoms. In E2 reactions, the stereochemistry of the starting material can lead to different stereoisomers in the products, such as cis and trans configurations, or E/Z isomers, depending on the orientation of substituents around the double bond formed.
Recommended video:
Guided course
01:58Determining when molecules are stereoisomers.
Regioselectivity and Stereoselectivity
Regioselectivity and stereoselectivity are important concepts in elimination reactions. Regioselectivity refers to the preference for the formation of one constitutional isomer over others, while stereoselectivity indicates the preference for one stereoisomer over another. In E2 reactions, the orientation of the leaving group and the hydrogen being removed can lead to different regio- and stereoisomeric products, which must be considered when predicting the outcomes.
Recommended video:
Guided course
05:09Heck Reaction
Related Practice
Textbook Question
Draw the elimination products for each of the following E2 reactions; if the products can exist as stereoisomers, indicate which stereoisomers are obtained.
d. (2R,3R)-2-chloro-3-methylpentane + high concentration of CH3O-
1473
views
Textbook Question
Draw the substitution products for each of the following SN2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed:
a. (3S,4S)-3-bromo-4-methylhexane + CH3O-
b. (3S,4R)-3-bromo-4-methylhexane + CH3O-
958
views
Textbook Question
Draw the elimination products for each of the following E2 reactions; if the products can exist as stereoisomers, indicate which stereoisomers are obtained.
c. (2R,3S)-2-chloro-3-methylpentane + high concentration of CH3O-
1487
views
Textbook Question
Draw the elimination products for each of the following E2 reactions; if the products can exist as stereoisomers, indicate which stereoisomers are obtained.
e. 3-chloro-3-ethyl-2,2-dimethylpentane + high concentration of CH3CH2O-
872
views
Textbook Question
Draw the substitution products for each of the following SN2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed:
c. (3R,4R)-3-bromo-4-methylhexane + CH3O-
d. (3R,4S)-3-bromo-4-methylhexane + CH3O-
863
views