Textbook Question
Two bromoethers are obtained from the reaction of the following alkyl dihalide with methanol. Draw the structures of the ethers.
1250
views
Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
Not the one you use?Change textbookSelect a different textbook
Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
All textbooks
Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblem 110c,d
Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblem 110c,dChapter 10, Problem 110c,d
Draw the substitution products for each of the following SN2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed:
c. (3R,4R)-3-bromo-4-methylhexane + CH3O-
d. (3R,4S)-3-bromo-4-methylhexane + CH3O-
Verified step by step guidance1
Step 1: Identify the type of substitution reaction. Since CH3O- is a strong nucleophile and a strong base, the reaction is likely to proceed via an SN2 mechanism. In SN2 reactions, the nucleophile attacks the carbon attached to the leaving group (bromine) from the opposite side, leading to inversion of configuration at the carbon center.
Step 2: Analyze the stereochemistry of the starting material for part (a). The compound (3R, 4R)-3-bromo-4-methylhexane has the bromine atom on the 3rd carbon in the R configuration and a methyl group on the 4th carbon in the R configuration. When CH3O- attacks the 3rd carbon, the configuration at this carbon will invert to S due to the backside attack characteristic of SN2 reactions.
Step 3: Draw the product for part (a). After the substitution, the bromine is replaced by the methoxy group (-OCH3), and the stereochemistry at the 3rd carbon is inverted to S. The 4th carbon retains its R configuration since it is not involved in the reaction.
Step 4: Analyze the stereochemistry of the starting material for part (b). The compound (3R, 4S)-3-bromo-4-methylhexane has the bromine atom on the 3rd carbon in the R configuration and a methyl group on the 4th carbon in the S configuration. When CH3O- attacks the 3rd carbon, the configuration at this carbon will invert to S due to the SN2 mechanism.
Step 5: Draw the product for part (b). After the substitution, the bromine is replaced by the methoxy group (-OCH3), and the stereochemistry at the 3rd carbon is inverted to S. The 4th carbon retains its S configuration since it is not involved in the reaction. If stereoisomers are possible, ensure to represent them clearly in the product structure.
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
3mWas this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Nucleophilic Substitution Reactions
Nucleophilic substitution reactions involve the replacement of a leaving group in a molecule by a nucleophile. In this context, the nucleophile is CH3O-, which attacks the carbon atom bonded to the bromine in the bromoalkane. Understanding the mechanism (either SN1 or SN2) is crucial, as it influences the stereochemistry of the products formed.
Recommended video:
Guided course
01:47
Nucleophiles and Electrophiles can react in Substitution Reactions.
Stereochemistry and Stereoisomers
Stereochemistry refers to the spatial arrangement of atoms in molecules and how this affects their chemical behavior. Stereoisomers are compounds that have the same molecular formula and connectivity but differ in the orientation of their atoms in space. In the given reactions, the stereochemistry of the starting materials will determine the types of stereoisomers produced, which may include enantiomers and diastereomers.
Recommended video:
1:38Polymer Stereochemistry Concept 1
Chirality and Optical Activity
Chirality is a property of a molecule that makes it non-superimposable on its mirror image, often due to the presence of a chiral center, typically a carbon atom with four different substituents. The presence of chirality in the products of the reactions can lead to optical activity, where the compounds can rotate plane-polarized light. Identifying chiral centers in the products is essential for determining the stereoisomers formed in the reactions.
Recommended video:
Guided course
08:17Mutorotation and Optical Activity
Related Practice
Textbook Question
Draw the elimination products for each of the following E2 reactions; if the products can exist as stereoisomers, indicate which stereoisomers are obtained.
d. (2R,3R)-2-chloro-3-methylpentane + high concentration of CH3O-
1473
views
Textbook Question
The rate of the reaction of methyl iodide with quinuclidine was measured in nitrobenzene, and then the rate of the reaction of methyl iodide with triethylamine was measured in the same solvent. The concentration of the reagents was the same in both experiments.
c. Which alkyl halide has the larger kquinuclidine/ktriethylamine ratio?
1486
views
Textbook Question
Draw the substitution products for each of the following SN2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed:
a. (3S,4S)-3-bromo-4-methylhexane + CH3O-
b. (3S,4R)-3-bromo-4-methylhexane + CH3O-
958
views
Textbook Question
Draw the elimination products for each of the following E2 reactions; if the products can exist as stereoisomers, indicate which stereoisomers are obtained.
c. (2R,3S)-2-chloro-3-methylpentane + high concentration of CH3O-
1487
views
Textbook Question
Draw the elimination products for each of the following E2 reactions; if the products can exist as stereoisomers, indicate which stereoisomers are obtained.
a. (2S,3S)-2-chloro-3-methylpentane + high concentration of CH3O−
b. (2S,3R)-2-chloro-3-methylpentane + high concentration of CH3O−
726
views