Textbook Question
a. Which of the following reactions has the larger ∆S° value?
b. Is the ∆S° value positive or negative?
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Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
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Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
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Bruice 8th EditionCh. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and KineticsProblem 62
Bruice 8th EditionCh. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and KineticsProblem 62Chapter 6, Problem 62
Using curved arrows, show the mechanism of the following reaction:
Verified step by step guidance1
Step 1: Identify the reactants and the type of reaction. In this case, the reaction involves acetaldehyde (CH₃CHO) and hydronium ion (H₃O⁺), leading to the formation of a protonated intermediate.
Step 2: Use curved arrows to show the first step of the mechanism. The lone pair of electrons on the oxygen atom of acetaldehyde attacks the hydrogen atom of the hydronium ion (H₃O⁺), forming a bond and resulting in the protonation of the carbonyl oxygen.
Step 3: Represent the intermediate structure. After protonation, the oxygen of acetaldehyde becomes positively charged, forming CH₃CHOH⁺. This step increases the electrophilicity of the carbonyl carbon.
Step 4: Show the nucleophilic attack by water (H₂O). The lone pair of electrons on the oxygen atom of water attacks the electrophilic carbonyl carbon, forming a bond and leading to the formation of a tetrahedral intermediate.
Step 5: Depict the final equilibrium. The tetrahedral intermediate rearranges, and a proton transfer occurs, resulting in the formation of a geminal diol (CH₃C(OH)₂) and regeneration of the hydronium ion (H₃O⁺).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Curved Arrows in Mechanisms
Curved arrows are used in organic chemistry to represent the movement of electrons during chemical reactions. They indicate the direction of electron flow, showing how bonds are formed or broken. Understanding how to draw and interpret these arrows is crucial for visualizing reaction mechanisms and predicting the outcome of reactions.
Recommended video:
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04:32
General Mechanism
Acid-Base Reactions
Acid-base reactions involve the transfer of protons (H⁺ ions) between reactants. In these reactions, an acid donates a proton while a base accepts it. Recognizing the roles of acids and bases in a reaction is essential for understanding the mechanism, as it helps identify the electron donors and acceptors involved.
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02:49The Lewis definition of acids and bases.
Resonance Structures
Resonance structures are different ways of drawing the same molecule that illustrate the delocalization of electrons. They are important in understanding the stability and reactivity of intermediates in a reaction mechanism. Recognizing resonance can help predict the most stable form of a molecule and its behavior during a reaction.
Recommended video:
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03:04Drawing Resonance Structures
Related Practice
Textbook Question
Draw the structure of a compound with molecular C8H14 that reacts with one equivalent of H2 over Pd/C to form a meso compound
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Textbook Question
Given that the free energy of the twist-boat conformer of cyclohexane is 5.3 kcal/mol greater than that of the chair conformer, calculate the percentage of twist-boat conformers present in a sample of cyclohexane at 25 °C. Does your answer agree with the statement made in Section 3.13 about the relative number of molecules in these two conformations?
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Textbook Question
For a reaction carried out at 25 °C with an equilibrium constant of 1 × 10-3, to increase the equilibrium constant by a factor of 10:
a. how much must ∆G° change?
b. how much must ∆H° change if ∆S° = 0 kcal mol-1 K-1?
c. how much must ∆S° change if ∆H° = 0 kcal mol-1?
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Textbook Question
From the following rate constants, determined at five temperatures, calculate the experimental energy of activation and ∆G‡, ∆H‡, and ∆S‡ for the reaction at 30 °C:
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Textbook Question
a. What is the equilibrium constant for a reaction that is carried out at 25 °C (298 K) with ∆H° = 20 kcal/mol and ∆S° = 5.0 × 10-2 kcal mol-1 K-1?
b. What is the equilibrium constant for the same reaction carried out at 125 °C?
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