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Multiple Choice
Evaluate the line integral of the function along the curve , where is given by the parametric equations , for . That is, compute .
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Step 1: Recall the formula for a line integral with respect to arc length: ∫_C f(x, y) ds. Here, f(x, y) = x y, and the curve C is parameterized by x = t^2 and y = 2t for 0 ≤ t ≤ 5.
Step 2: Compute the derivatives of the parametric equations with respect to t. For x = t^2, dx/dt = 2t. For y = 2t, dy/dt = 2.
Step 3: Use the formula for arc length differential ds = √((dx/dt)^2 + (dy/dt)^2) dt. Substitute dx/dt = 2t and dy/dt = 2 into the formula: ds = √((2t)^2 + 2^2) dt = √(4t^2 + 4) dt.
Step 4: Substitute the parametric equations x = t^2 and y = 2t into f(x, y) = x y. This gives f(x, y) = (t^2)(2t) = 2t^3.
Step 5: Set up the integral ∫_C f(x, y) ds in terms of t. Substitute f(x, y) = 2t^3 and ds = √(4t^2 + 4) dt into the integral: ∫_C x y ds = ∫_0^5 (2t^3)(√(4t^2 + 4)) dt. Evaluate this integral to find the final result.