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Multiple Choice
Evaluate the definite integral:
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Verified step by step guidance
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Step 1: Recognize that the integral \( \int_1^5 w^2 \ln(w) \, dw \) involves a product of functions \( w^2 \) and \( \ln(w) \). This suggests using integration by parts, which is based on the formula \( \int u \, dv = uv - \int v \, du \).
Step 2: Choose \( u = \ln(w) \) (since its derivative simplifies) and \( dv = w^2 \, dw \) (since its integral is straightforward). Compute \( du = \frac{1}{w} \, dw \) and \( v = \frac{w^3}{3} \).
Step 3: Substitute into the integration by parts formula: \( \int_1^5 w^2 \ln(w) \, dw = \left[ \frac{w^3}{3} \ln(w) \right]_1^5 - \int_1^5 \frac{w^3}{3} \cdot \frac{1}{w} \, dw \). Simplify the second integral to \( \int_1^5 \frac{w^2}{3} \, dw \).
Step 4: Evaluate the first term \( \left[ \frac{w^3}{3} \ln(w) \right]_1^5 \) by substituting the limits \( w = 5 \) and \( w = 1 \). Then, compute the second integral \( \int_1^5 \frac{w^2}{3} \, dw \) by finding the antiderivative of \( \frac{w^2}{3} \), which is \( \frac{w^3}{9} \), and applying the limits.
Step 5: Combine the results from the first term and the second integral, ensuring proper subtraction and simplification. The final expression will match the correct answer \( \frac{125}{3} \ln(5) - \frac{124}{9} \).