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Multiple Choice
Evaluate the line integral , where C is the line segment from to .
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Verified step by step guidance
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Step 1: Understand the problem. The line integral \( \int_C (2x + 3y) \, dx + (x - y) \, dy \) is to be evaluated along the line segment \( C \) from \( (0, 0) \) to \( (2, 4) \). This involves parameterizing the curve \( C \) and substituting into the integral.
Step 2: Parameterize the line segment \( C \). Since \( C \) is a straight line from \( (0, 0) \) to \( (2, 4) \), we can use the parameter \( t \) such that \( x = 2t \) and \( y = 4t \), where \( t \) ranges from \( 0 \) to \( 1 \).
Step 3: Compute \( dx \) and \( dy \) in terms of \( t \). Differentiating \( x = 2t \) gives \( dx = 2 \, dt \), and differentiating \( y = 4t \) gives \( dy = 4 \, dt \).
Step 4: Substitute \( x = 2t \), \( y = 4t \), \( dx = 2 \, dt \), and \( dy = 4 \, dt \) into the integral. The integral becomes \( \int_0^1 [(2(2t) + 3(4t))(2) + ((2t) - (4t))(4)] \, dt \).
Step 5: Simplify the integrand and evaluate the integral. Combine terms inside the brackets, simplify, and integrate with respect to \( t \) over the interval \( [0, 1] \). This will yield the final result.