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Multiple Choice
Let . What is the average value of on the interval ?
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Verified step by step guidance
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Step 1: Recall the formula for the average value of a function f(x) on the interval [a, b], which is given by \( \text{Average Value} = \frac{1}{b-a} \int_{a}^{b} f(x) \, dx \).
Step 2: Identify the interval [a, b] from the problem. Here, \( a = 0 \) and \( b = 32 \). Substitute these values into the formula.
Step 3: Substitute \( f(x) = x^{1/5} \) into the integral. The formula becomes \( \text{Average Value} = \frac{1}{32-0} \int_{0}^{32} x^{1/5} \, dx \).
Step 4: Compute the integral \( \int_{0}^{32} x^{1/5} \, dx \). Use the power rule for integration: \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), where \( n = \frac{1}{5} \). Apply this rule to find the antiderivative of \( x^{1/5} \).
Step 5: Evaluate the definite integral by substituting the limits of integration (0 and 32) into the antiderivative. Then divide the result by 32 to find the average value.