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Multiple Choice
Let . What is the average value of on the interval ?
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Verified step by step guidance
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Step 1: Recall the formula for the average value of a function f(x) on the interval [a, b], which is given by \( \text{Average Value} = \frac{1}{b-a} \int_{a}^{b} f(x) \, dx \).
Step 2: Identify the interval [a, b] and the function f(x). Here, \( a = 0 \), \( b = 16 \), and \( f(x) = x^{1/2} \). Substitute these values into the formula.
Step 3: Set up the integral \( \int_{0}^{16} x^{1/2} \, dx \). Recall that \( x^{1/2} \) is the same as \( x^{1/2} = x^{0.5} \). Use the power rule for integration: \( \int x^{n} \, dx = \frac{x^{n+1}}{n+1} + C \).
Step 4: Apply the power rule to compute \( \int x^{0.5} \, dx \). This gives \( \frac{x^{1.5}}{1.5} \), or equivalently \( \frac{2}{3} x^{1.5} \). Evaluate this expression at the bounds of the interval [0, 16].
Step 5: Substitute the evaluated integral result into the average value formula \( \text{Average Value} = \frac{1}{16-0} \int_{0}^{16} x^{1/2} \, dx \). Simplify the expression to find the average value of the function on the interval.