Skip to main content
Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 11, Problem 11.2.26

Radius and interval of convergence Determine the radius and interval of convergence of the following power series.


∑ₖ₌₁∞ (3x + 2)ᵏ/k

Verified step by step guidance
1
Identify the given power series: \( \sum_{k=1}^{\infty} \frac{(3x + 2)^k}{k} \). This is a power series centered at the point where the expression inside the power is zero, so first find the center by solving \(3x + 2 = 0\).
Solve for \(x\) to find the center of the series: \(3x + 2 = 0 \implies x = -\frac{2}{3}\). This means the series is centered at \(x = -\frac{2}{3}\).
To find the radius of convergence, use the root test or ratio test. Here, the root test is convenient. Consider the general term \(a_k = \frac{(3x + 2)^k}{k}\). The root test involves calculating \( \lim_{k \to \infty} \sqrt[k]{|a_k|} \).
Calculate the limit: \( \lim_{k \to \infty} \sqrt[k]{\left| \frac{(3x + 2)^k}{k} \right|} = \lim_{k \to \infty} \frac{|3x + 2|}{\sqrt[k]{k}} = |3x + 2| \), since \( \sqrt[k]{k} \to 1 \) as \(k \to \infty\).
Set the limit less than 1 for convergence: \( |3x + 2| < 1 \). Solve this inequality for \(x\) to find the interval of convergence. Then, check the endpoints \( |3x + 2| = 1 \) separately by substituting back into the original series to determine if the series converges or diverges at those points.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
7m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Power Series and Convergence

A power series is an infinite sum of terms in the form a_k(x - c)^k, where c is the center. Understanding convergence means determining for which values of x the series sums to a finite value. This is essential to analyze the behavior of the series and find where it converges.
Recommended video:
05:58
Intro to Power Series

Radius of Convergence

The radius of convergence is the distance from the center c within which the power series converges absolutely. It can be found using tests like the Ratio Test or Root Test. Knowing the radius helps identify the interval on the x-axis where the series behaves well.
Recommended video:
07:36
Radius of Convergence

Interval of Convergence

The interval of convergence includes all x-values for which the power series converges, typically centered at c and extending radius R in both directions. Endpoints must be checked separately for convergence. This interval defines the domain where the series represents a valid function.
Recommended video:
08:44
Interval of Convergence
Related Practice
Textbook Question

{Use of Tech} Newton's derivation of the sine and arcsine series Newton discovered the binomial series and then used it ingeniously to obtain many more results. Here is a case in point.

a. Referring to the figure, show that x = sin s or s = sin ⁻¹ x.

b. The area of a circular sector of radius r subtended by an angle θ is 1/2r²θ. Show that the area of the circular sector APE is s/2, which implies that

s = 2 ∫₀ˣ √(1 − t²) dt − x √(1 −x²)

c. Use the binomial series for f(x) = √(1 − x²) to obtain the first few terms of the Taylor series for s=sin ⁻¹ x.

d. Newton next inverted the series in part (c) to obtain the Taylor series for x=sin s. He did this by assuming sin s = ∑ aₖ sᵏ and solving x = sin(sin ⁻¹ x) for the coefficients aₖ. Find the first few terms of the Taylor series for sin s using this idea (a computer algebra system might be helpful as well).

124
views
Textbook Question

{Use of Tech} Maximum error Use the remainder term to find a bound on the error in the following approximations on the given interval. Error bounds are not unique.


tan x ≈ x on [−π/6, π/6]

89
views
Textbook Question

Exponential function In Section 11.3, we show that the power series for the exponential function centered at 0 is


eˣ = ∑ₖ₌₀∞ (xᵏ)/k!, for −∞ < x < ∞


Use the methods of this section to find the power series centered at 0 for the following functions. Give the interval of convergence for the resulting series.


f(x) = e⁻³ˣ

86
views
Textbook Question

{Use of Tech} Approximating powers Compute the coefficients for the Taylor series for the following functions about the given point a, and then use the first four terms of the series to approximate the given number.

f(x) =∛x with a=64; approximate ∛60.

55
views
Textbook Question

Working with binomial series Use properties of power series, substitution, and factoring to find the first four nonzero terms of the Maclaurin series for the following functions. Use the Maclaurin series


(1 + x)⁻² = 1 − 2x + 3x² − 4x³ + ⋯, for −1 < x < 1.


(1 + 4x)⁻²

59
views
Textbook Question

Inverse sine Given the power series

1/√(1 − x²) = 1 + (1/2)x² + (1 ⋅ 3)/(2 ⋅ 4) x⁴ + (1 ⋅ 3 ⋅ 5)/(2 ⋅ 4 ⋅ 6) x⁶ +⋯

for −1<x<1, find the power series for f(x) = sin ⁻¹ x centered at 0.

65
views