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Ch. 2 - Limits
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
All textbooksBriggs 3rd EditionCh. 2 - LimitsProblem 2.2.27
Chapter 2, Problem 2.2.27

Use a graph of f to estimate limx→af(x){\(\displaystyle\]\lim\)_{x\(\to\) a}f\(\left\)(x\(\right\))} or to show that the limit does not exist. Evaluate f(x) near x=ax=a to support your conjecture.
f(x)=x−2ln∣x−2∣f\(\left\)(x\(\right\))=\(\frac{x-2}{\ln\left|x-2\right|}\); a=2a=2

Verified step by step guidance
1
Identify the function and the point of interest: We have \( f(x) = \frac{x-2}{\ln|x-2|} \) and we are interested in the limit as \( x \to 2 \).
Recognize the indeterminate form: As \( x \to 2 \), both the numerator \( x-2 \) and the denominator \( \ln|x-2| \) approach 0, indicating a \( \frac{0}{0} \) indeterminate form.
Apply L'Hôpital's Rule: Since we have a \( \frac{0}{0} \) form, we can use L'Hôpital's Rule, which involves differentiating the numerator and the denominator separately.
Differentiate the numerator and denominator: The derivative of the numerator \( x-2 \) is 1, and the derivative of the denominator \( \ln|x-2| \) is \( \frac{1}{x-2} \).
Evaluate the new limit: Substitute the derivatives back into the limit expression to get \( \lim_{x \to 2} \frac{1}{\frac{1}{x-2}} \), which simplifies to \( \lim_{x \to 2} (x-2) \). Analyze this limit to determine if it exists or not.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Limits

A limit describes the behavior of a function as its input approaches a certain value. It is essential for understanding continuity and the behavior of functions near points where they may not be explicitly defined. In this context, we are interested in the limit of f(x) as x approaches 2, which helps determine the function's value or behavior at that point.
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Continuity

A function is continuous at a point if the limit of the function as it approaches that point equals the function's value at that point. For the function f(x) given, checking continuity at x = 2 involves evaluating the limit as x approaches 2 and comparing it to f(2). If they are not equal, the function is discontinuous at that point.
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Indeterminate Forms

Indeterminate forms occur in calculus when evaluating limits leads to expressions like 0/0 or ∞/∞, which do not provide clear information about the limit's value. In this case, as x approaches 2, both the numerator and denominator of f(x) approach 0, indicating an indeterminate form. Techniques such as L'Hôpital's Rule or algebraic manipulation may be needed to resolve these forms and find the limit.
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Related Practice
Textbook Question

Evaluate limx→∞f(x){\(\displaystyle\[\lim\)_{x\(\to\]\infty\)}{f(x)}} andlimx→−∞f(x){\(\displaystyle\]\lim\)_{x\(\to\)-\(\infty\)}{f(x)}}.


f(x)=4x3+11−x3f\(\left\)(x\(\right\))=\(\frac{4x^3+1}{1-x^3}\)

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Determine the following limits.

lim w→∞ (ln w2) / (ln w3 + 1)

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Describe the end behavior of g(x) = e-2x.

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Evaluate each limit and justify your answer. 

lim x→0 (x^8−3x^6−1)^40

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Textbook Question

Find the following limits or state that they do not exist. Assume a, b, c, and k are fixed real numbers.


limx→01−cos(x)cos2(x)−3cos(x)+2{\(\displaystyle\]\lim\)_{x\(\to\)0}\(\frac{1-\cos\left(x\right)}{\cos^2\left(x\right)-3\cos\left(x\right)+2}\)}

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Textbook Question

Determine limx→∞f(x)\(\lim\)_{x\(\rightarrow\]\infty\)}f\(\left\)(x\(\right\)) and limx→−∞f(x)\(\lim\)_{x\(\rightarrow\)-\(\infty\)}f\(\left\)(x\(\right\)) for the following functions. Then give the horizontal asymptotes of ff (if any).


f(x)=4x3+12x3+16x6+1f\(\left\)(x\(\right\))=\(\frac{4x^3+1}{2x^3+\sqrt{16x^6+1}\)}

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