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Ch. 6 - Applications of Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 6, Problem 6.1.50b

Blood flow A typical human heart pumps 70 mL of blood (the stroke volume) with each beat. Assuming a heart rate of 60 beats/min (1 beat/s), a reasonable model for the outflow rate of the heart is V′(t)=70(1+sin 2πt), where V(t) is the amount of blood (in milliliters) pumped over the interval [0,t],V(0)=0 and t is measured in seconds.


b. Find the function that gives the total blood pumped between t=0 and a future time t>0.

Verified step by step guidance
1
Identify the given rate of blood flow as the derivative of the volume function: \(V'(t) = 70(1 + \sin(2\pi t))\) milliliters per second.
Recall that to find the total volume pumped over time, you need to find the original function \(V(t)\) by integrating the rate function \(V'(t)\) with respect to \(t\).
Set up the integral: \(V(t) = \int 70(1 + \sin(2\pi t)) \, dt\).
Split the integral into two parts for easier integration: \(V(t) = 70 \int 1 \, dt + 70 \int \sin(2\pi t) \, dt\).
Integrate each part separately, remembering to include the constant of integration \(C\), and then use the initial condition \(V(0) = 0\) to solve for \(C\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Understanding the Derivative as a Rate of Change

The derivative V′(t) represents the instantaneous rate at which blood is pumped by the heart at time t. Recognizing that V′(t) is the rate of change of the total volume V(t) is essential to relate the given function to the total blood pumped over time.
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Intro To Related Rates

Definite Integration to Find Accumulated Quantity

To find the total blood pumped from time 0 to t, we integrate the rate function V′(t) over [0, t]. Integration accumulates the instantaneous rates over time, yielding the total volume V(t). This process reverses differentiation and uses the initial condition to find the constant of integration.
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Definition of the Definite Integral

Applying Initial Conditions to Determine the Integration Constant

Since V(0) = 0, the initial amount of blood pumped is zero. After integrating V′(t), we use this initial condition to solve for the constant of integration, ensuring the function V(t) accurately models the total blood volume pumped starting from zero.
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Initial Value Problems Example 1
Related Practice
Textbook Question

Variable gravity At Earth’s surface, the acceleration due to gravity is approximately g=9.8 m/s² (with local variations). However, the acceleration decreases with distance from the surface according to Newton’s law of gravitation. At a distance of y meters from Earth’s surface, the acceleration is given by a(y) = - g / (1+y/R)², where R=6.4×10⁶ m is the radius of Earth.


b. Use the Chain Rule to show that dv/dt = 1/2 d/dy(v²).

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Textbook Question

Determine whether the following statements are true and give an explanation or counterexample.


b. The area of the region between y=sin x and y=cos x on the interval [0,π/2] is ∫π/20(cosx−sinx)dx.

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Textbook Question

Distance traveled and displacement Suppose an object moves along a line with velocity (in ft/s) v(t)=6−2t, for 0≤t≤6, where t is measured in seconds.


b. Find the displacement of the object on the interval 0≤t≤6.

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Textbook Question

40–43. Population growth


Starting with an initial value of P(0)=55, the population of a prairie dog community grows at a rate of P′(t)=20−t/5 (prairie dogs/month), for 0≤t≤200, where t is measured in months.


b. Find the population P(t), for 0≤t≤200.

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Textbook Question

Filling a tank A 2000-liter cistern is empty when water begins flowing into it (at t=0 at a rate (in L/min) given by Q′(t) = 3√t, where t is measured in minutes.


b. Find the function that gives the amount of water in the tank at any time t≥0.

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Textbook Question

55–58. Marginal cost Consider the following marginal cost functions.


b. Find the additional cost incurred in dollars when production is increased from 500 units to 550 units.


C′(x) = 300+10x−0.01x²

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